Q.5 In spectrophotometric measurement of proteins. which of the amino acids contribute the maximum?
1. Tyrosine. Phenylalanine, Tryptophan
2. Tyrosine, Serine, Threonine
3. Phenylalanine, Alanine. Leucine
4. Histidine. Proline, Twptophan
Tyrosine, Phenylalanine, and Tryptophan are the amino acids that contribute the maximum to spectrophotometric measurement of proteins at 280 nm.
Question Solution
This multiple-choice question tests knowledge of UV absorbance in protein quantification, where aromatic amino acids dominate due to their conjugated ring systems absorbing strongly at 280 nm.
Option Analysis
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Option 1: Tyrosine, Phenylalanine, Tryptophan
Correct. Tryptophan shows the strongest absorbance (ε ≈ 5500 M⁻¹ cm⁻¹), tyrosine next (ε ≈ 1400 M⁻¹ cm⁻¹), and phenylalanine weakest (ε ≈ 200 M⁻¹ cm⁻¹) among amino acids. All three aromatic residues drive A280 readings, with Trp dominating protein spectra. -
Option 2: Tyrosine, Serine, Threonine
Incorrect. Serine and threonine lack aromatic rings and have negligible absorbance at 280 nm; only tyrosine contributes significantly here. -
Option 3: Phenylalanine, Alanine, Leucine
Incorrect. Alanine and leucine are non-aromatic aliphatics with no 280 nm absorbance; phenylalanine contributes minimally compared to Trp/Tyr. -
Option 4: Histidine, Proline, Tryptophan
Incorrect. Histidine (imidazole) and proline (cyclic) absorb weakly below 280 nm; tryptophan contributes, but the others do not match the trio’s impact.
Proteins are quantified routinely via spectrophotometric measurement at 280 nm (A280), relying on specific amino acids’ UV absorbance from aromatic rings. In spectrophotometric measurement of proteins, tyrosine, phenylalanine, and tryptophan contribute the maximum due to their π-conjugated systems.
Key Absorbing Amino Acids
Tryptophan (Trp) provides the highest molar absorptivity, making it the primary contributor—its indole ring peaks sharply at 280 nm. Tyrosine (Tyr) follows with its phenolic ring, while phenylalanine (Phe) adds lesser but detectable absorbance via its benzene ring. Disulfide bonds and other residues are minor.
Why 280 nm?
This wavelength targets aromatic residues without interference from peptide bonds (≈220 nm). Proteins vary in content (e.g., 1-2% Trp), so extinction coefficients are calculated: A280 = (n_Trp × 5500 + n_Tyr × 1400 + n_Phe × 200)/path length.
Practical Applications
In labs, A280 estimates concentration (e.g., 1 A280 ≈ 1 mg/mL for IgG). For pure proteins, it’s quick and reagent-free; fluorescence enhances sensitivity via Trp/Tyr emission. Exam prep tip: Always prioritize Trp > Tyr > Phe for such questions.