Q.17 The value of ionic product of water changes with temperature. It is 1 × 10−14 at 25 °C and 1 × 10−13 at 60 °C. The CORRECT statement with respect to ΔH and ΔS is: (A) ΔH is negative and ΔS is negative (B) ΔH is positive and ΔS is zero (C) ΔH is positive and ΔS is negative (D) ΔH is negative and ΔS is positive

Q.17 The value of ionic product of water changes with temperature. It is
1 × 10−14 at 25 °C and 1 × 10−13 at 60 °C.
The CORRECT statement with respect to ΔH and ΔS is:

(A) ΔH is negative and ΔS is negative
(B) ΔH is positive and ΔS is zero
(C) ΔH is positive and ΔS is negative
(D) ΔH is negative and ΔS is positive

Thermodynamic Nature of Ionic Product of Water (Kw) with Temperature

The ionic product of water (Kw) represents the extent of auto-ionization of water.
Its variation with temperature provides important information about the
enthalpy change (ΔH) and entropy change (ΔS)
of the reaction.


Correct Answer

Option (C): ΔH is positive and ΔS is negative


Thermodynamic Explanation

Auto-ionization of Water

H2O (l) ⇌ H+ (aq) + OH (aq)

Enthalpy Change (ΔH)

Since the value of Kw increases with temperature,
the forward reaction is favored at higher temperature.
This indicates that the reaction is endothermic.

Therefore, ΔH > 0.

Entropy Change (ΔS)

The formation of hydrated H+ and OH ions
causes increased ordering of surrounding water molecules.
This results in a net decrease in randomness.

Therefore, ΔS < 0.


Option-wise Analysis

Option (A): Incorrect — an exothermic reaction would show a decrease in Kw with temperature.

Option (B): Incorrect — entropy change cannot be zero due to ion hydration.

Option (C): Correct — increase in Kw confirms ΔH > 0 and hydration causes ΔS < 0.

Option (D): Incorrect — neither enthalpy nor entropy trend matches experimental data.


Final Conclusion

The increase in ionic product of water with temperature shows that
the auto-ionization of water is an endothermic process
accompanied by a decrease in entropy.


Final Answer

Correct Option: (C) ΔH is positive and ΔS is negative

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