![Q.20 According to crystal field theory, the electronic configuration of [Ti(H2O)6]3+ in the ground state is Options: (A) eg1 t2g0 (B) t2g0 eg1 (C) eg0 t2g1 (D) t2g1 eg0](data:image/svg+xml;base64,PHN2ZyB2aWV3Qm94PSIwIDAgMTkyMCAxMDgwIiB3aWR0aD0iMTkyMCIgaGVpZ2h0PSIxMDgwIiB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciPjwvc3ZnPg==)
Q.20 According to crystal field theory, the electronic configuration of
[Ti(H2O)6]3+ in the ground state is
Options:
(A) eg1 t2g0
(B) t2g0 eg1
(C) eg0 t2g1
(D) t2g1 eg0
Electronic Configuration of [Ti(H2O)6]3+
Crystal Field Theory (CFT) explains the splitting of d-orbitals in the
presence of ligands. Using this theory, we determine the
ground state electronic configuration of the
octahedral complex
[Ti(H2O)6]3+.
Step 1: Oxidation State of Titanium
H2O is a neutral ligand and the overall charge on the complex
is +3.
Oxidation state of Ti = +3
Step 2: d-Electron Count
Atomic number of Ti = 22
Electronic configuration of Ti:
[Ar] 3d2 4s2
Ti3+ loses 3 electrons (2 from 4s and 1 from 3d).
Number of d-electrons = 1
Step 3: Nature of the Complex
- Ligand: H2O (weak field ligand)
- Geometry: Octahedral
- Spin state: High spin
Step 4: d-Orbital Splitting
In an octahedral field, the d-orbitals split into:
- Lower energy: t2g
- Higher energy: eg
The single d-electron occupies the lower energy t2g orbital.
Ground State Electronic Configuration
t2g1 eg0
Correct Answer
Option (D)
Summary Table
| Parameter | Value |
|---|---|
| Metal ion | Ti3+ |
| d-electron count | 1 |
| Geometry | Octahedral |
| Ground state configuration | t2g1 eg0 |
Conclusion
According to crystal field theory, the single d-electron in
[Ti(H2O)6]3+ occupies the lower-energy
t2g orbital.
Hence, the correct answer is Option (D).
