Q. 5 A number consists of two digits. The sum of the digits is 9. If 45 is subtracted from the number, its digits are interchanged. What is the number? (A) 63 (B) 72 (C) 81 (D) 90

Q. 5 A number consists of two digits. The sum of the digits is 9. If 45 is subtracted from the number,
its digits are interchanged. What is the number?

  • (A) 63
  • (B) 72
  • (C) 81
  • (D) 90

A two-digit number has a digit sum of 9. When 45 is subtracted from the number,
the digits of the number get interchanged. Find the number.

Correct Answer: 72

Problem Setup

Let the two-digit number be represented as:

10a + b, where:

  • a = tens digit
  • b = units digit

Given conditions:

a + b = 9  …(1)

After subtracting 45, digits reverse:

(10a + b) − 45 = 10b + a

Mathematical Solution

Simplify the equation:

10a + b − 45 = 10b + a

9a − 9b = 45

a − b = 5  …(2)

Now solve the system of equations:

a + b = 9
a − b = 5

Adding both equations:

2a = 14 → a = 7

Substitute a = 7:

b = 2

The required number = 72

Option Analysis

Option Number Digit Sum After Subtracting 45 Digits Reversed?
(A) 63 6 + 3 = 9 18 No (Reverse = 36)
(B) 72 7 + 2 = 9 27 Yes
(C) 81 8 + 1 = 9 36 No (Reverse = 18)
(D) 90 9 + 0 = 9 45 No (Reverse = 09)

Final Conclusion

Only 72 satisfies both conditions:

  • Digits add up to 9
  • Digits reverse after subtracting 45

Final Answer: 72

 

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