10. Possible combination of gametes which can be formed by genotype AaBbCcDdEeFfGg are?
(1) 16              (2) 32
(3) 64              (4) 128

Step-by-step reasoning

Genotype: AaBbCcDdEeFfGg

Each gene is heterozygous (A/a, B/b, C/c, D/d, E/e, F/f, G/g).

For each heterozygous pair, meiosis can place either allele in a gamete.

Thus each pair contributes 2 possibilities.

Number of heterozygous pairs n = 7.

Use the standard formula for possible gametes:

Number of gametes = 2ⁿ = 2⁷ = 128

So this individual can form 128 different gamete types.

Checking options

• 16 → 2⁴, would correspond to 4 heterozygous pairs (not 7).
• 32 → 2⁵, for 5 heterozygous pairs.
• 64 → 2⁶, for 6 heterozygous pairs.
• 128 → 2⁷, matches 7 heterozygous pairs in AaBbCcDdEeFfGg.

Therefore, the correct choice is option (4) 128.