- From population dynamics point of view, what would be the effective population size of a population of 150 breeding females and 50 breeding males?
(1) 200 (2) 100
(3) 150 (4) 50The Effective Population Size Formula
For populations with different numbers of breeding males ($N_m$) and females ($N_f$), the standard formula is:
Ne=4NmNfNm+Nf
Where:
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$N_m$ = Number of breeding males
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$N_f$ = Number of breeding females
This formula shows that unequal sex ratios reduce effective population size, increasing the risk of genetic drift and loss of genetic diversity.
Calculation Example: 150 Females and 50 Males
Given:
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$N_m = 50$
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$N_f = 150$
Plug the values into the formula:
Ne=4×50×15050+150Ne=4×7,500200Ne=30,000200Ne=150
Therefore, the effective population size for a population with 150 breeding females and 50 breeding males is 150.
Why Effective Population Size Matters
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Genetic Drift: Smaller $N_e$ means stronger genetic drift, leading to faster loss of genetic diversity.
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Inbreeding: Low $N_e$ increases the risk of inbreeding and the expression of harmful genetic traits.
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Conservation: Conservation programs use $N_e$ to assess population health and design breeding strategies to maximize genetic diversity.
Key Takeaways
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The effective population size is not always equal to the census size—unequal sex ratios can significantly reduce $N_e$.
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In this example, even with 200 breeding individuals, the effective population size is 150 due to the 3:1 female-to-male ratio.
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Maintaining a balanced sex ratio is important for maximizing $N_e$ and preserving genetic diversity in both wild and managed populations.
Correct answer:
(3) 150 -