From population dynamics point of view, what would be the effective population size of a population of 150 breeding females and 50 breeding males? (1) 200 (2) 100 (3) 150 (4) 50
  1. From population dynamics point of view, what would be the effective population size of a population of 150 breeding females and 50 breeding males?
    (1) 200 (2) 100
    (3) 150 (4) 50

     

    The Effective Population Size Formula

    For populations with different numbers of breeding males ($N_m$) and females ($N_f$), the standard formula is:

    Ne=4NmNfNm+Nf

    Where:

    • $N_m$ = Number of breeding males

    • $N_f$ = Number of breeding females

    This formula shows that unequal sex ratios reduce effective population size, increasing the risk of genetic drift and loss of genetic diversity.

    Calculation Example: 150 Females and 50 Males

    Given:

    • $N_m = 50$

    • $N_f = 150$

    Plug the values into the formula:

    Ne=4×50×15050+150Ne=4×7,500200Ne=30,000200Ne=150

    Therefore, the effective population size for a population with 150 breeding females and 50 breeding males is 150.

    Why Effective Population Size Matters

    • Genetic Drift: Smaller $N_e$ means stronger genetic drift, leading to faster loss of genetic diversity.

    • Inbreeding: Low $N_e$ increases the risk of inbreeding and the expression of harmful genetic traits.

    • Conservation: Conservation programs use $N_e$ to assess population health and design breeding strategies to maximize genetic diversity.

    Key Takeaways

    • The effective population size is not always equal to the census size—unequal sex ratios can significantly reduce $N_e$.

    • In this example, even with 200 breeding individuals, the effective population size is 150 due to the 3:1 female-to-male ratio.

    • Maintaining a balanced sex ratio is important for maximizing $N_e$ and preserving genetic diversity in both wild and managed populations.

    Correct answer:
    (3) 150

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