16. In semi-conservative mode of DNA replication twoparental strands unwind and are used for synthesis of new strands following the rule of complimentary base pairing. Synthesis of complimentary strands requirethat DNA synthesis proceeds in opposite direction,while the double helix is progressively unwinding andreplicating in only one direction.one of the DNA strands is continuously synthesised in the same direction as theadvancing replication fork and is called leading strandstrands is synthesized the otherwhereasdiscontinuously in segments and is referred to aslagging strands. These short fragments madediscontinuously are labelled as okazaki fragments.These okazaki fragments need to be matured intocontinuous DNA strand by which one of the followingcombination of enzymes? (1) DNA Pol III and DNA ligase (2) DNA pol I and DNA ligase (3) DNA pol II and DNA ligase (4) DNA gyrase and DNA ligase
  1. In semi-conservative mode of DNA replication twoparental strands unwind and are used for synthesis of new strands following the rule of complimentary base

pairing. Synthesis of complimentary strands requirethat DNA synthesis proceeds in opposite direction,while the double helix is progressively unwinding andreplicating in only one direction.one of the DNA strands

is continuously synthesised in the same direction as theadvancing replication fork and is called leading strandstrands

is synthesized the otherwhereasdiscontinuously in segments and is referred to aslagging strands. These short fragments madediscontinuously are labelled as okazaki fragments.These okazaki fragments need to be matured intocontinuous DNA strand by which one of the followingcombination of enzymes?
(1) DNA Pol III and DNA ligase

(2) DNA pol I and DNA ligase

(3) DNA pol II and DNA ligase

(4) DNA gyrase and DNA ligase

 


Introduction

During semi-conservative DNA replication, the two parental strands unwind and serve as templates for new complementary strands. Because DNA polymerases synthesize DNA only in the 5′ to 3′ direction, replication of the two antiparallel strands occurs differently:

  • The leading strand is synthesized continuously in the direction of the replication fork.

  • The lagging strand is synthesized discontinuously in short segments called Okazaki fragments.

These Okazaki fragments must be processed and joined to form a continuous DNA strand. This maturation involves the removal of RNA primers, gap filling, and sealing of nicks, which requires specific enzymes.


Formation of Okazaki Fragments

  • The lagging strand template runs 5′ to 3′, so DNA polymerase synthesizes new DNA in short stretches moving away from the replication fork.

  • Each Okazaki fragment starts with an RNA primer synthesized by primase.

  • DNA polymerase extends these primers to form short DNA fragments.

  • This discontinuous synthesis necessitates a maturation process to join fragments into a continuous strand.


Enzymes Involved in Okazaki Fragment Maturation

  1. DNA Polymerase I

    • Possesses 5′→3′ exonuclease activity that removes RNA primers from the Okazaki fragments.

    • Fills in the resulting gaps with DNA nucleotides, synthesizing DNA to replace the removed RNA.

  2. DNA Ligase

    • Seals the nicks (breaks in the sugar-phosphate backbone) between adjacent Okazaki fragments by forming phosphodiester bonds.

    • This action completes the synthesis of a continuous lagging strand.


Other Enzymes and Their Roles

  • DNA Polymerase III:

    • The primary enzyme responsible for synthesizing new DNA strands during replication, including the bulk of the lagging strand synthesis.

    • Does not remove RNA primers or seal nicks.

  • DNA Polymerase II:

    • Functions mainly in DNA repair, not in Okazaki fragment maturation.

  • DNA Gyrase:

    • A topoisomerase that relieves supercoiling ahead of the replication fork, unrelated to Okazaki fragment processing.


Summary Table

Enzyme Combination Role in Okazaki Fragment Maturation Correctness for Maturation
DNA Pol III and DNA ligase DNA synthesis and nick sealing, but no primer removal Incorrect
DNA Pol I and DNA ligase Removes RNA primers, fills gaps, and seals nicks Correct
DNA Pol II and DNA ligase DNA repair and nick sealing, not primer removal Incorrect
DNA Gyrase and DNA ligase Relieves supercoiling and nick sealing Incorrect

Correct Answer

(2) DNA Polymerase I and DNA ligase


Conclusion

The maturation of Okazaki fragments during semi-conservative DNA replication is a crucial step to ensure the lagging strand becomes a continuous DNA molecule. This process requires the coordinated action of DNA Polymerase I, which removes RNA primers and fills in the gaps with DNA, and DNA ligase, which seals the nicks between fragments. Together, these enzymes maintain the integrity and continuity of the newly synthesized DNA strand.

31 Comments
  • Manisha choudhary
    July 25, 2025

    😎😎🤓🤓🔥

  • Divyanshi Vaishnav
    July 27, 2025

    👍🏻

  • Divyanshi Vaishnav
    July 27, 2025

    👍🏻👍🏻

  • Divyanshi Vaishnav
    July 27, 2025

    Good questions

  • Sneha kumawat
    July 28, 2025

    👍

  • Khushi Agarwal
    July 29, 2025

    Answer is dna pol 1 and ligase
    Dna pol 1 – remove rna primer and add ntd on that place
    Ligase – join fragments and form pdb bond

  • Pratibha
    July 29, 2025

    Correct option is option (2)
    DNA polymerase 1 possess 5′-3′ exonuclease activity which removes RNA primers and fill the gap with DNA nucleotides and synthesize the new DNA strand

    DNA ligase seals the nicks by forming phospho diester bonds between two adjacent okazaki fragments

  • anurag giri
    July 29, 2025

    Ans 2 bcoz pol 1 fistt remove old nucleotide of rna and replace with new nt of dna when prime’s all nt replaced then bind by ligase

  • Vanshika Sharma
    July 29, 2025

    Dna pol 1 and dna ligase .
    DNA pol 1 will remove the primer and in last dna ligase will form PDB bw them. Working as a glue bw them

  • Surbhi Rajawat
    July 29, 2025

    Answer is
    Pol 1 (to remove the RNA primers by 5 prime to 3 prime exonuclease activity)
    DNA ligase (to form PDB)

  • Diksha Chhipa
    July 29, 2025

    DNA pol 1 have 5to 3 prime exonuclease activity so answer is dna pol 1 nd ligase

  • Mansukh Kapoor
    July 29, 2025

    The correct answer is option 2nd because pol 1 removes the primer and ligase binds or seals the end of the fragments

  • Heena
    July 29, 2025

    Dna pol 1 that’s function is to remove primers and complete the sequence by its polymerase activity and dna ligase joins the existing oh and phosphorus with help of atp

  • shruti sharma
    July 29, 2025

    pol1 and DNA ligase

  • Priti Khandal
    July 29, 2025

    Dna polymerase 1 and ligase okazaki fragment ko jodne me help karta h

  • Priya Khandal
    July 29, 2025

    DNA Polymers first and ligase

  • HIMANI FAUJDAR
    July 30, 2025

    Answer is DNA polymerase 1 and ligase
    DNA polymerase 1 – have 5′-3′ exonucleus activity that removes RNA primer and ligase used to seals the nick.

  • Priya Dhakad
    July 30, 2025

    The correct option is 2 becoz DNA polymerase 1 have 5′-3′ exonuclease activity which removes RNA primers and fill in the gap and ligase seals the nick

  • Payal Gaur
    July 30, 2025

    DNA polymerase 1st remove primer fill the gap and DNA seal by ligase enzyme.

  • Aafreen
    July 30, 2025

    Ans-2 DNA Polymerase I is responsible for removing the RNA primers that initiate the synthesis and DNA ligase forms the phosphodiester bonds between DNA segments and fill the gaps

  • Deepika Sheoran
    July 30, 2025

    Dna polymerase 1st removes the primer fill in the gap&Dna seal by ligase enzyme.
    Dna polymerase have 5’_3′ exonuclease activity.

  • Anisha jakhar
    July 31, 2025

    Option 2. Polymerase 1 and DNA ligase

  • Dipti Sharma
    July 31, 2025

    DNA Polymerase I have 5′→3′ exonuclease activity that removes RNA primers from the Okazaki fragments and ligase seals the gap between existing nucleotides.
    so, option 2 is correct

  • Avni
    July 31, 2025

    DNA Polymerase I have 5′→3′ exonuclease activity and removes RNA primers and DNA Ligase Seal nick between adjacent Okazaki fragments

  • Aman Choudhary
    July 31, 2025

    DNA pol 1 and ligase is correct answer DNA pol 1 remove Rna primer and Dna ligase seal the nick b/w okazaki fragments

  • Khushi Mehra
    August 1, 2025

    Dna polymerase 1 remove the primer from okazaki fragments and add dNTPs .
    Ligase seal the gap between two lagging strand by forming phosohodiester bond between nucleotides.
    Answer is 2

  • Santosh Saini
    August 1, 2025

    Option 2nd is correct bcz pol.1 remove RNA primer and fill gaps, ligase form pdb and seal the nick

  • Mahima Sharma
    August 2, 2025

    👍🏻

  • Soniya Shekhawat
    August 3, 2025

    DNA pol 1 has remove primer and DNA ligase seal nick .so option 2 is correct.

  • Anita Choudhary
    August 28, 2025

    DNApol1 and ligase

  • Deepika Sheoran
    November 6, 2025

    DNA polymerase 1st removes the primer fill in the gap and DNA seal by ligase enzyme.
    DNA polymerase have 5′-3′ Exonuclease Activity.

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