Q.45 Consider the data set 14, 18, 14, 14, 10, 29, 33, 31, 25. If you add 20 to each of the values, then (A) both mean and variance change (B) both mean and variance are unchanged (C) the mean is unchanged, variance changes (D) the mean changes, the variance is unchanged

Q.45 Consider the data set 14, 18, 14, 14, 10, 29, 33, 31, 25. If you add 20 to each of the values, then
(A) both mean and variance change (B) both mean and variance are unchanged
(C) the mean is unchanged, variance changes (D) the mean changes, the variance is unchanged

Adding Constant to Dataset: Mean Changes, Variance Stays Same – Statistics MCQ Explained

Adding a constant like 20 to every value in a dataset shifts the mean by that amount but leaves variance unchanged, as variance measures spread relative to the mean. For the dataset 14, 18, 14, 14, 10, 29, 33, 31, 25, the correct answer is (D) the mean changes, the variance is unchanged.

Original Dataset Stats

The original mean is sum (14+18+14+14+10+29+33+31+25=188) divided by 9, yielding about 20.89. Variance is the average of squared deviations from this mean, roughly 61.11 (population formula). Standard deviation is sqrt(variance) ≈ 7.82.

Effect After Adding 20

New values: 34, 38, 34, 34, 30, 49, 53, 51, 45. New mean = 20.89 + 20 = 40.89 (shifts by constant). New variance remains 61.11, since deviations (e.g., 34-40.89 = -6.89 matches original 14-20.89) square identically.

Why Variance Unchanged

Variance formula: σ² = (1/n) Σ(xi - x̄)². Adding c=20 makes new points yi = xi + c, new mean ȳ = x̄ + c, so yi - ȳ = xi - x̄. Squared differences stay same.

Options Breakdown

(A) Both mean and variance change

Incorrect; variance invariant to shifts.

(B) Both mean and variance unchanged

Incorrect; mean shifts by 20.

(C) Mean unchanged, variance changes

Incorrect; mean changes, variance stable.

(D) Mean changes, variance unchanged

Correct, as proven above.

 

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