Q.44 In Michaelis-Menten’s equation, if [S] = 15 Km , then the ratio 𝑣0/𝑉max is __________. (Round off to three decimal places)

Q.44 In MichaelisMenten’s equation, if [S] = 15 Km , then the ratio 𝑣0/𝑉max is __________.
(Round off to three decimal places)


The ratio v0/Vmax is 0.938 when [S] = 15 Km in the Michaelis-Menten equation.

Michaelis-Menten Equation

The Michaelis-Menten equation describes enzyme kinetics: v0 = Vmax[S]/(Km + [S]). Dividing both sides by Vmax gives the velocity ratio: v0/Vmax = [S]/(Km + [S]). Substituting [S] = 15 Km yields v0/Vmax = 15Km/(Km + 15Km) = 15/16 = 0.9375, which rounds to 0.938.

Detailed Calculation

Start with the ratio formula: [S]/Km / (1 + [S]/Km). Here, [S]/Km = 15, so 15/(1+15) = 15/16. Compute 15 ÷ 16 = 0.9375; rounding to three decimal places gives 0.938 per standard convention.

Step-by-Step Solution

  1. Normalize: Let [S]/Km = 15
  2. Ratio = 15/(1+15) = 15/16
  3. 15 ÷ 16 = 0.9375 → 0.938 (three decimals)

Common Ratios Explained

[S]/Km v0/Vmax Saturation Level
1 Km 0.500 Half saturation
9 Km 0.900 90% saturation
15 Km 0.938 93.8% saturation
99 Km ≈0.990 Near saturation

No options provided, but these illustrate saturation trends; 15 Km gives high velocity (93.8% of max).

Biological Significance

High [S] (15 Km) means near-zero-order kinetics—velocity plateaus as enzyme saturates. Km reflects enzyme-substrate affinity; low Km = high affinity.

CSIR NET Exam Tips

  • Practice derivations without calculator
  • Remember: [S] = 10 Km → 0.909; scales predictably
  • Use Lineweaver-Burk plots for verification: 1/v vs 1/[S]
  • This matches CSIR NET patterns, like [S]=3 Km (0.750) or 9 Km (0.900)

Final Answer

0.938

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