52. During photosynthetic carbon reduction cycle in green leaves, net production of one molecule of glyceraldehyde 3-phosphate requires one of the following combinations of energy equivalents:
(1) 9 NADPH and 6 ATP (2) 3 NADPH and 9 ATP.
(3) 2 NADPH and 3 ATP (4) 6 NADPH and 9 ATP.
Introduction
Understanding the ATP and NADPH requirement for producing one net glyceraldehyde 3-phosphate (G3P) in the Calvin cycle is a frequent concept question in NEET and other entrance exams. The key is to remember the overall stoichiometry of CO₂ fixation and the number of energy equivalents consumed to form one triose phosphate that actually leaves the cycle.
Core concept and correct answer
The overall balanced equation for the photosynthetic carbon reduction (Calvin) cycle to produce one net molecule of glyceraldehyde 3-phosphate from 3 molecules of CO₂ is commonly written as:
3 CO₂ + 9 ATP + 6 NADPH + 6 H₂O → 1 G3P + 9 ADP + 8 Pi + 6 NADP⁺.
This clearly shows that net production of one G3P requires 9 ATP and 6 NADPH, so among the given options, “6 NADPH and 9 ATP” is the only correct combination.
Biochemically, ATP is used in both the reduction of 3‑phosphoglycerate to G3P and the regeneration of ribulose 1,5‑bisphosphate, while NADPH provides the reducing power in the reduction stage.
Why option (4) is correct: 6 NADPH and 9 ATP
Option (4) states that one net G3P requires 6 NADPH and 9 ATP, which matches the standard Calvin cycle stoichiometry for fixation of 3 CO₂.
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For each CO₂ molecule fixed in a C₃ plant, 3 ATP and 2 NADPH are required, so for 3 CO₂, the total becomes 9 ATP and 6 NADPH, giving one net G3P that can exit the cycle.
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This G3P can subsequently be used to form glucose, sucrose, starch, and other carbohydrates, but the Calvin cycle energy requirement is defined at the level of net triose phosphate formation.
Because the question explicitly asks for “net production of one molecule of glyceraldehyde 3-phosphate,” not just a single reduction step, the full cycle requirement (9 ATP, 6 NADPH) is the correct answer.
Why option (3) looks familiar but is incomplete: 2 NADPH and 3 ATP
Option (3): “2 NADPH and 3 ATP” is actually the requirement to fix one molecule of CO₂, not to produce one net G3P leaving the cycle.
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Per CO₂, the Calvin cycle uses 3 ATP and 2 NADPH; this comes from 2 molecules of 3‑phosphoglycerate formed and then reduced to G3P, plus regeneration reactions.
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One net G3P requires 3 CO₂, so the per‑CO₂ values must be multiplied by 3, giving 9 ATP and 6 NADPH; using only 2 NADPH and 3 ATP would account for only one-third of the needed energy.
Thus, option (3) is numerically correct per CO₂ but wrong for “net one G3P,” which is why it is not the right choice in this question.
Why option (1) is wrong: 9 NADPH and 6 ATP
Option (1) reverses the correct ratio, claiming 9 NADPH and 6 ATP, which does not match the known Calvin cycle energy balance.
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The Calvin cycle uses more ATP than NADPH; standard teaching emphasizes that 3 ATP are required for every 2 NADPH, so ATP:NADPH is 3:2, not the other way round.
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If 9 NADPH and 6 ATP were required, this would imply more reducing power than phosphorylation energy, contradicting the experimentally determined stoichiometry and the coupling with the light reactions.
Therefore, option (1) misrepresents both the absolute numbers and the ATP:NADPH ratio, making it incorrect.
Why option (2) is wrong: 3 NADPH and 9 ATP
Option (2) suggests 3 NADPH and 9 ATP, which also fails to match the recognized energy requirement of the Calvin cycle.
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Although 9 ATP is correct for one net G3P, the number of NADPH molecules must be 6, not 3; halving the NADPH would leave the reduction steps of 1,3‑bisphosphoglycerate to G3P underpowered.
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The consistent ratio of 3 ATP to 2 NADPH would predict that if ATP is 9, NADPH must be 6; any other combination violates that fixed ratio and so cannot be correct for normal C₃ photosynthesis.
Thus, option (2) mixes a correct ATP value with an incorrect NADPH value and must be rejected.
In summary, the photosynthetic carbon reduction cycle in green leaves requires 6 NADPH and 9 ATP for the net production of one glyceraldehyde 3-phosphate, making option (4) the correct answer.



1 Comment
Sakshi Kanwar
November 30, 20259 ATP and 6 NADPH molecules for one turns and for three turns total 18 ATP and 12 NADPH