Q.62 A container originally contains 10 litres of pure spirit. From this container 1 litre of spirit is replaced with 1 litre of water. Subsequently, 1 litre of the mixture is again replaced with 1 litre of water and this process is repeated one more time. How much spirit is now left in the container? (A) 7.58 litres (B) 7.84 litres (C) 7 litres (D) 7.29 litres

Q.62 A container originally contains 10 litres of pure spirit. From this container 1 litre of spirit is replaced with 1 litre of water. Subsequently, 1 litre of the mixture is again replaced with 1 litre of water and this process is repeated one more time. How much spirit is now left in the container?

(A) 7.58 litres

(B) 7.84 litres

(C) 7 litres

(D) 7.29 litres

 

Option (D) 7.29 Litres

After three 1L replacements from 10L pure spirit:

Final Spirit = 10 × (9/10)³ = 10 × 0.729 = 7.29L

 Master Formula: Successive Dilution

Final Amount = Initial × (1 – Fraction Removed)n
Here: 10 × (9/10)3 = 10 × 0.729 = 7.29L

Each replacement removes 10% of current mixture, compounding geometrically.

 Detailed Step-by-Step Calculation

0

Initial: 10L pure spirit

1

Step 1: Remove 1L → 9L spirit + 1L water = 90%

2

Step 2: Remove 0.9L spirit → 8.1L spirit = 81%

3

Step 3: Remove 0.81L spirit → 7.29L

Option Amount Calculation Error ✅ Correct?
(A) 7.58L Overestimates remaining ❌ Wrong
(B) 7.84L 10 × (0.9)² only (2 steps) ❌ Wrong
(C) 7L Linear: 10 – 1×3 (no compounding) ❌ Wrong
(D) 7.29L 10 × 0.9³ = 7.29 ✓ ✅ CORRECT

 Exam Shortcuts & Pro Tips

  • 🔥 Pattern Recognition: Same volume replaced = geometric series
  • Instant Formula: V₀ × (1 – r/V)ⁿ
  • Quick Check: 3 steps × 10% removal ≈ 73% left (7.3L range)
  • 🚫 Avoid Traps: Linear math (7L), partial compounding (7.84L)
  • 💡 Pro Tip: Calculate (1 – fraction removed)ⁿ first → 0.9³ = 0.729!

🚨 Common Mistakes Explained

  • 7.84L (B): Forgot 3rd replacement, did only (0.9)²
  • 7L (C): Simple subtraction ignores mixture concentration
  • 7.58L (A): Wrong formula or calculator error

 

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