(DEC 2012) 70. An enzyme catalyzed reaction was measured in the presence and absence of an inhibitor for an uncompetitive inhibition, (1) only Km is increased (2) only is Vmax decreased (3) both Km and Vmax are decreased (4) both Km and Vmax are not affected

(DEC 2012)
70. An enzyme catalyzed reaction was measured in the presence and absence of an inhibitor for an uncompetitive inhibition,
(1) only Km is increased
(2) only is Vmax decreased
(3) both Km and Vmax are decreased
(4) both Km and Vmax are not affected

The correct answer is (3) both Km and Vmax are decreased.


Introduction

Enzyme inhibition is a vital aspect of biochemical regulation and drug action, with uncompetitive inhibition being a distinct mode where the inhibitor binds exclusively to the enzyme-substrate (ES) complex. This unique binding mode causes simultaneous decreases in both the Michaelis constant (Km) and the maximum reaction velocity (Vmax), distinguishing uncompetitive inhibition from other types. This article elaborates on the mechanism and kinetic consequences of uncompetitive inhibition to clarify how and why Km and Vmax both decrease.


Mechanism of Uncompetitive Inhibition

  • The uncompetitive inhibitor binds only to the enzyme-substrate complex (ES), forming an inactive ESI complex.

  • This binding prevents product formation, trapping the enzyme in an inactive state.

  • Because the inhibitor binds after substrate binding, it does not affect substrate affinity in a typical way but lowers the apparent Km due to shift in equilibrium.


Effects on Kinetic Parameters

  • Decrease in Vmax:

    • The effective concentration of active enzyme is reduced because some enzyme is locked in the inactive ESI complex, lowering the maximum achievable reaction rate.

  • Decrease in apparent Km:

    • The inhibitor binding shifts equilibrium towards ES complex formation, effectively increasing enzyme’s apparent affinity for substrate, reducing Km.


Mathematical Relationships

  • Modified Michaelis-Menten equation with inhibitor:

V=(Vmax/(1+[I]/Ki))[S](Km/(1+[I]/Ki))+[S]

  • Both Vmax and Km are divided by the same factor, lowering their observable values in kinetics.


Distinguishing Uncompetitive Inhibition Graphs

  • Lineweaver-Burk plots show parallel lines for inhibited and uninhibited reactions.

  • Both slopes and intercepts change proportionally, reflecting simultaneous decreases in Km and Vmax.


Comparison Table of Inhibition Types

Inhibition Type Km Effect Vmax Effect Inhibitor Binding Site
Competitive Increases Unchanged Active site
Non-competitive Unchanged Decreases Allosteric site
Uncompetitive Decreases Decreases Enzyme-substrate complex (ES)

Biological and Pharmaceutical Implications

  • Uncompetitive inhibitors can be highly effective at high substrate concentrations because they bind exclusively to ES.

  • Their distinct kinetic signature aids in identifying binding modes and designing targeted inhibitors.


Conclusion

In uncompetitive inhibition, both Km and Vmax decrease due to inhibitor binding the ES complex, trapping the enzyme-substrate form and preventing product formation. Option (3) both Km and Vmax are decreased correctly describes this inhibition type.


This detailed review strengthens biochemical understanding of inhibition kinetics, aiding students and researchers in enzyme characterization and drug discovery.

55 Comments
  • yashika
    September 12, 2025

    Both km vmax decrease for uncompetitive

    • Mahima Sharma
      September 17, 2025

      Both km and Vmax are decreases

  • Kirti Agarwal
    September 12, 2025

    In uncompetative inhibitors affinity increase for ESI complex so Km is reduced
    Vmax is always decrease in uncompetative

  • Khushi Vaishnav
    September 12, 2025

    Both Km and Vmax are decreased

  • anjani sharma
    September 12, 2025

    In uncompetative inhibition both v max and km decrease

  • Sakshi yadav
    September 12, 2025

    Both km and vmax decrease

  • Bharti yadav
    September 12, 2025

    Km and Vmax are decreased

  • Varsha Tatla
    September 13, 2025

    Both are decrease

  • Savita Garwa
    September 13, 2025

    (3) both Km and Vmax are decreased.

  • Kajal
    September 13, 2025

    Option 3 is correct as both km and vmax decreases in uncompetitive binding

    • Gupta isha
      September 14, 2025

      Both km &vmax are decreased

  • Kanica Sunwalka
    September 13, 2025

    in uncompetitive inhibition both km and v max – decreases

  • Aakansha sharma Sharma
    September 13, 2025

    both Km and Vmax are decreased.

  • Rishita
    September 13, 2025

    Both km and vmax decrease

  • Pratibha Jain
    September 14, 2025

    correct answer is option (3)
    both Km and Vmax are decreased.

  • Santosh Saini
    September 14, 2025

    In uncompetitive inhibition both the Vmax and Km decreased

  • Anju
    September 14, 2025

    Ans: 3
    Both km and Vmax are decrease

  • Aartii sharma
    September 14, 2025

    Both vmax and km is decreased

  • Dharmpal Swami
    September 14, 2025

    Both km and Vmax.are decreased

  • Konika Naval
    September 14, 2025

    both Km and Vmax are decreased.

  • Pooja
    September 14, 2025

    Option c is correct
    both Km and Vmax are decreased

  • Pallavi Ghangas
    September 14, 2025

    In uncomfortable inhibition both we VMax and km decrease

  • Deepika sheoran
    September 14, 2025

    Both Vmax & Km are decreased.

  • Deepika sheoran
    September 14, 2025

    Both Vmax & Km are decreased.

  • Ankita Pareek
    September 14, 2025

    Both km and v max decreased

  • Palak Sharma
    September 14, 2025

    (3) both Km and Vmax are decreased.

  • Vijay kumar Meena
    September 14, 2025

    Km and Vmax are decreased and affinity increase

  • Ajay Sharma
    September 14, 2025

    Both , km and Vmax are decreased

  • Gupta isha
    September 14, 2025

    Both km &vmax are decreased

  • HIMANI FAUJDAR
    September 14, 2025

    Ans In uncompetitive inhibition both Km and Vmax decrease due to inhibitor binding the ES complex and Prevent Product formation.

  • Priya dhakad
    September 14, 2025

    In uncompetitive inhibition, both vmax and km decrease.

  • Sakshi Kanwar
    September 14, 2025

    The inhibitor binds after substrate binding, it does not affect substrate affinity in a typical way but lowers the apparent Km and Vmax

  • Soniya Shekhawat
    September 15, 2025

    The uncompetitive inhibitor binds only to the enzyme-substrate complex (ES), forming an inactive ESI complex so km and vmax is Decrease

  • Vanshika Sharma
    September 15, 2025

    Both km and Vmax are decreased

  • Devika
    September 15, 2025

    Both km and Vmax are decreased

  • Mohd juber Ali
    September 15, 2025

    Both Vmax and Km are decrease

  • Lokesh Kumawat
    September 15, 2025

    Both km and Vmax are decreased

  • Bhawna Choudhary
    September 15, 2025

    Both km and vmax is decreased in uncompetitive inhibition

  • Mansukh Kapoor
    September 15, 2025

    The correct answer is option 3rd
    Both Km and Vmax are decreased

  • Aafreen Khan
    September 16, 2025

    In uncompetitive inhibition the inhibitor binds to ES complex and form ESI complex
    So both km and Vmax decreases

  • Anjana sharma
    September 16, 2025

    Both km and vmax decreased in uncompetitive inhibition

  • Nilofar Khan
    September 16, 2025

    correct answer is (3) both Km and Vmax are decreased.

  • Tanvi Panwar
    September 16, 2025

    Both Km and Vmax. are decreased.

  • Payal Gaur
    September 16, 2025

    Both km and Vmax are decrease

  • priti khandal
    September 17, 2025

    both vmax and km is decrease

  • Khushi Agarwal
    September 17, 2025

    Correct Answer: 3both Km and Vmax are decreased Uncompetitive inhibition me inhibitor sirf ES complex ko block karta hai ← substrate nikal hi nahi pata, isliye enzyme “trap” ho jata hai values (Km aur Vmax) gir jaati hain. ← dono

  • Simran Saini
    September 17, 2025

    Both Km and Vmax are decreased.

  • Avni
    September 17, 2025

    correct answer is (3) both Km and Vmax are decreased.

  • Sonal Nagar
    September 19, 2025

    Option 3

  • Asha Gurzzar
    September 19, 2025

    Both km and vmax decrease

  • Minal Sethi
    September 19, 2025

    both km and vmax are decreased

  • Muskan Yadav
    September 19, 2025

    both Km and Vmax are decreased.

  • Kajal
    September 25, 2025

    The correct answer is (3) both Km and Vmax are decreased

  • Priti khandal
    September 29, 2025

    C is right

  • Sachin kant sharma
    September 29, 2025

    Uncompetative:- km or vmax both decrease

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