(JUNE 2008) 30. For an enzyme catalyzed reactions exhibiting Michalis Menten equation what would be increase in substrate concentration to increase the rate of reaction from 10 % of Vmax to 90 % of Vmax (1) 81 fold (2) 8 fold (3) 4 fold (4) 2 fold

(JUNE 2008)
30. For an enzyme catalyzed reactions exhibiting Michalis Menten equation what would be increase in substrate concentration to increase the rate of reaction from 10 % of Vmax to 90 % of Vmax
(1) 81 fold                                                  (2) 8 fold
(3) 4 fold                                                    (4) 2 fold

The correct answer is (1) 81 fold.


Introduction

Michaelis-Menten kinetics describe the relationship between enzyme reaction velocity and substrate concentration. Understanding how substrate concentration changes affect reaction velocity is crucial in enzymology, drug design, and metabolic regulation. This article calculates the fold increase in substrate concentration required to increase the enzymatic rate from 10% to 90% of Vmax and explains the significance of this change using the Michaelis-Menten model.


Michaelis-Menten Equation Recap

The equation relating initial velocity V0 to substrate concentration [S] is:

V0=Vmax[S]Km+[S]

Where

  • V0 = initial velocity

  • Vmax = maximum velocity

  • Km = Michaelis constant

  • [S] = substrate concentration


Calculations

Step 1: Substrate concentration at 10% Vmax

Set V0=0.1Vmax:

0.1Vmax=Vmax[S1]Km+[S1]

Simplify by dividing both sides by Vmax:

0.1=[S1]Km+[S1]

Cross multiply:

0.1(Km+[S1])=[S1]0.1Km+0.1[S1]=[S1]

Subtract 0.1[S1] from both sides:

0.1Km=0.9[S1]

Solve for [S1]:

[S1]=0.1Km0.9=Km9


Step 2: Substrate concentration at 90% Vmax

Set V0=0.9Vmax, similarly:

0.9=[S2]Km+[S2]0.9(Km+[S2])=[S2]0.9Km+0.9[S2]=[S2]0.9Km=0.1[S2][S2]=0.9Km0.1=9Km


Step 3: Fold increase in substrate concentration

Fold increase=[S2][S1]=9KmKm9=81


Interpretation

  • To increase the reaction velocity from 10% to 90% of Vmax, substrate concentration must be increased 81-fold.

  • This demonstrates the non-linear relationship between substrate concentration and reaction rate typical of Michaelis-Menten kinetics.


Practical Significance

  • Explains why enzymes respond sensitively to substrate changes near low concentrations.

  • Guides experimental design to achieve desired enzymatic rates.

  • Informs pharmacokinetic models for drug metabolism and enzyme-targeted therapies.


Summary Table

Reaction Velocity (% Vmax) Substrate Concentration ([S])
10% Km9
90% 9Km
Fold increase 81

Conclusion

Using the Michaelis-Menten equation, increasing substrate concentration from Km9 to 9Km increases enzyme reaction rate from 10% to 90% of Vmax, corresponding to an 81-fold increase in substrate concentration. This highlights the enzyme’s saturation kinetics and its implications for both biological systems and experimental enzyme studies.

27 Comments
  • Aakansha sharma Sharma
    September 12, 2025

    Calculate S1 when Vo=10/100Vmax=0.1Vmax
    0.1Vmax=VmaxS/Km+S
    0.1Km+0.1S=S
    0.1Km=1S-0.1S
    0.1Km=0.9S
    S=0.1Km/0.9
    s1=1Km/9
    Calculate when S2 is
    Vo=90/100 of Vmax=0.9Vmax
    0.9Vmax=VmaxS/Km+S
    0.9km+0.9S=S
    0.9Km=1S-0.9S
    0.9Km=0.1S
    S2=0.9Km/0.1=9Km
    So know we have both S2&S1 so we calculate Fold increase=S2/S1=9Km/1/9Km=9×9= 81 fold

  • Varsha Tatla
    September 13, 2025

    Initially we will calculate the S1and S2
    Nd then we calculate fold increase by s2÷s1
    Thus, we will find 81 folds

  • Khushi Vaishnav
    September 13, 2025

    81 fold

  • Kanica Sunwalka
    September 13, 2025

    0.9Vmax = Vmax S / Km + S – FOR S2
    ————————————————
    0.1 Vmax =Vmax S / Km+ S – FOR S1
    ans is 81 fold

  • Mohd juber Ali
    September 14, 2025

    81 fold

  • Pooja
    September 14, 2025

    Option a is correct

  • Kirti Agarwal
    September 14, 2025

    81 fold

  • Anurag Giri
    September 14, 2025

    Initially we will calculate the S1and S2
    Nd then we calculate fold increase by s2÷s1
    Thus, we will find 81 folds

  • Khushi Agarwal
    September 14, 2025

    S1= 1/9km
    S2= 9km
    S2/S1= 81 folds

  • Anju
    September 14, 2025

    Ans:81 folds

  • Rishita
    September 14, 2025

    Initially we will calculate the S1and S2
    Nd then we calculate fold increase by s2÷s1
    Thus, we will find 81 folds

  • Neha Yadav
    September 14, 2025

    81 fold

  • Santosh Saini
    September 14, 2025

    81 fold

  • Vanshika Sharma
    September 14, 2025

    81 fold

  • Tanvi Panwar
    September 14, 2025

    0.1Vmax.=Vmax.S1/km+S1= 1/9km
    0.9Vmax.=Vmax.S2/Km+S2=9km
    so fold increase= S2/S1=81 folds.

  • Ayush Dubey
    September 14, 2025

    81 fold

  • Shivani
    September 14, 2025

    81 fold

  • Payal Gaur
    September 14, 2025

    81 fold

  • Pallavi Ghangas
    September 14, 2025

    81 fold

  • Nilofar Khan
    September 15, 2025

    Correct answer is (1)81 fold

  • Asha Gurzzar
    September 15, 2025

    1is correct answer 81 fold

  • Muskan singodiya
    September 15, 2025

    81 fold

  • Arushi Saini
    September 15, 2025

    Initially we will calculate the S1and S2
    Nd then we calculate fold increase by s2÷s1
    Thus, we will find 81 folds

  • Anjana sharma
    September 16, 2025

    81 fold.

  • Palak Sharma
    September 16, 2025

    Initially we will calculate the S1and S2
    Nd then we calculate fold increase by s2÷s1
    Thus, we will find 81 folds

  • Muskan Yadav
    September 17, 2025

    Initially we will calculate the S1and S2
    and then we calculate fold increase by s2÷s1
    Thus, we will find 81 folds is the correct answer.

  • Deepika sheoran
    September 18, 2025

    81 Fold

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