If frequency of one allele is 0.2 and another is 0.8 then number of homozygotes in population of 250 is (assume that population is in Hardy-Weinberg equilibrium)? (1) 32 (2) 10 (3) 40 (4) 170
  1. If frequency of one allele is 0.2 and another is 0.8 then number of homozygotes in population of 250 is (assume that population is in Hardy-Weinberg equilibrium)?
    (1) 32 (2) 10
    (3) 40 (4) 170

     

    Calculating Homozygotes in a Hardy-Weinberg Population: Step-by-Step Guide

    The Hardy-Weinberg equilibrium is a cornerstone of population genetics, providing a mathematical framework to predict genotype frequencies from allele frequencies in a non-evolving population. If you know the frequencies of two alleles in a population, you can easily calculate the expected number of homozygotes and heterozygotes. Let’s walk through a practical example using a population of 250 individuals with two alleles at frequencies 0.2 and 0.8.

    Step 1: Understanding the Hardy-Weinberg Equation

    The Hardy-Weinberg equation for a gene with two alleles (let’s call them A and a) is:

    p2+2pq+q2=1

    Where:

    • p = frequency of allele A

    • q = frequency of allele a

    • p2 = frequency of homozygous AA

    • q2 = frequency of homozygous aa

    • 2pq = frequency of heterozygous Aa

    Step 2: Assigning Allele Frequencies

    Given:

    • Frequency of one allele (p) = 0.2

    • Frequency of the other allele (q) = 0.8

    Check: p+q=0.2+0.8=1

    Step 3: Calculating Genotype Frequencies

    • Homozygous for allele 1 (AA): p2=(0.2)2=0.04

    • Homozygous for allele 2 (aa): q2=(0.8)2=0.64

    • Heterozygotes (Aa): 2pq=2×0.2×0.8=0.32

    Step 4: Calculating Number of Homozygotes in the Population

    Total population = 250

    • Number of AA homozygotes: 0.04×250=10

    • Number of aa homozygotes: 0.64×250=160

    • Total number of homozygotes: 10+160=170

    Step 5: Identifying the Correct Answer

    From the options provided:

    • (1) 32

    • (2) 10

    • (3) 40

    • (4) 170

    The correct answer is (4) 170.

    Why This Matters

    Knowing how to calculate genotype frequencies using the Hardy-Weinberg principle is essential for:

    • Predicting genetic disease risk in populations

    • Understanding population structure and evolution

    • Detecting deviations from equilibrium, which may indicate evolutionary forces at work

    Conclusion

    If the frequency of one allele is 0.2 and the other is 0.8 in a population of 250 individuals at Hardy-Weinberg equilibrium, the number of homozygotes in the population is 170. This includes both types of homozygotes (AA and aa).

    Correct answer: (4) 170

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