(SEPT 2022-1)
34. A student was asked to plot a graph representing enzyme kinetic data for initial velocity, vO , and substrate concentration [S] using any of the equations given below. The student used an equation for which neither X-axis nor Y-axis had independent variables. Which one of the
following equation might the student have used?
(1) 1/ vO = (Km/Vmax) 1/[S]+ 1/Vmax)
(2) [S]/vO = [S]/Vmaxx + (Km /Vmax)
(3) vO / [S] = (Vmax / Km) – vO / Km
(4) vO = V max [S] / Km + [S]
The correct answer is (3) v0[S]=VmaxKm−v0Km.
Introduction
Enzyme kinetics often involves transforming variables to linearize the Michaelis-Menten equation for easier extraction of kinetic constants. In some cases, the chosen equations produce plots where neither the x-axis nor y-axis is fully independent, meaning both variables share dependent components. Identifying such cases helps avoid misinterpretations and selects suitable plotting strategies. This article explains which enzyme kinetic equation produces a plot without independent variables on either axis, emphasizing its formation and utility.
The Equations and Their Variables
The four given equations for enzyme kinetics involve initial velocity v0, substrate concentration [S], and constants Vmax and Km:
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Lineweaver-Burk equation:
1v0=KmVmax1[S]+1Vmax
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X-axis: 1[S] (independent)
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Y-axis: 1v0 (dependent)
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Hanes-Woolf equation:
[S]v0=[S]Vmax+KmVmax
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X-axis: [S] (independent)
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Y-axis: [S]v0 (dependent)
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Eadie-Hofstee type rearrangement:
v0[S]=VmaxKm−v0Km
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X-axis: v0 (dependent variable)
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Y-axis: v0[S] (dependent variable)
Both axes depend on v0, so neither axis contains an independent variable.
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Michaelis-Menten original equation:
v0=Vmax[S]Km+[S]
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X-axis: [S] (independent)
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Y-axis: v0 (dependent)
Why Does Equation (3) Fit the Criteria?
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Both axes in equation (3) depend on v0.
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This dependence means the student using equation (3) plots a graph where neither axis is independently controlled.
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Such plots are also called ratio plots and are useful in certain kinetic analyses but have unique interpretative traits.
Significance of Equation (3) in Enzyme Kinetics
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Rearranged form of the Michaelis-Menten equation.
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Useful in Eadie-Hofstee plots, where velocity is plotted against velocity normalized by substrate concentration.
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Provides a linear plot from which Km and Vmax can be derived.
Summary Table of Plot Types
| Equation Number | Plot Variables (X-axis, Y-axis) | Independent Variable on Axis? | Common Usage |
|---|---|---|---|
| 1 | 1/[S], 1/v0 | X-axis only | Lineweaver-Burk plot |
| 2 | [S], [S]/v0 | X-axis only | Hanes-Woolf plot |
| 3 | v0, v0/[S] | None | Eadie-Hofstee plot |
| 4 | [S], v0 | X-axis only | Michaelis-Menten standard |
Conclusion
Among the provided equations, only equation (3)—v0[S]=VmaxKm−v0Km—yields a plot where neither the X nor Y axis represents an independent variable, hence fitting the student’s scenario. This plot type facilitates enzyme kinetics analysis but requires careful interpretation due to both variables’ interdependence.
23 Comments
Aakansha sharma Sharma
September 12, 2025The correct answer is (3) v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0. Bez it depends on variable it is Eadie hofstee plot
Varsha Tatla
September 13, 2025Option 3rd gives correct explanation
Khushi Vaishnav
September 13, 2025v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0.
Kajal
September 14, 2025Option c is correct as here both the x and y axis have dependent variables
Sakshi yadav
September 14, 2025v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0.
Pooja
September 14, 2025Option c is correct answer
Kanica Sunwalka
September 14, 2025ANS 3 is correct
Rishita
September 14, 2025v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0
Santosh Saini
September 14, 2025Correct answer is option 3
Bhawna Choudhary
September 14, 2025Option 3 is correct answer
Manisha choudhary
September 14, 2025Option 3 is correct
Anurag Giri
September 15, 2025The correct answer is (3) v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0. Bez it depends on variable it is Eadie hofstee plot
Nilofar Khan
September 15, 2025Correct answer is c
Vo/[s] = Vmax/Km – Vo/km
Payal Gaur
September 15, 2025C. Vo/S=VmX/km-Vo/Km
Mansukh Kapoor
September 15, 2025The correct answer is option 3rd
Because in this there is no independent variables in x -axis and y-axis
Pallavi Ghangas
September 15, 20253
Kirti Agarwal
September 15, 2025Opt 3
Anjana sharma
September 16, 2025v0=Vmax[S]Km+[S]v0=Km+[S]Vmax[S]
Palak Sharma
September 16, 20253
Palak Sharma
September 16, 2025eadie hofstee type rearrangement
Muskan Yadav
September 17, 2025v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0. Eadie-Hofstee plot is shown
Minal Sethi
September 18, 2025option 3 Eadie Hofstee equation
Deepika sheoran
September 18, 2025Option 3 rd is correct
Vo/S =Vmax/Km-Vo/Km