12.
The following line graph gives the ratio of the amount of entry to the amount of exit of a
specific molecule from a cell, over the time period 1-7 hours. If the entry at 4 hours was
250 units and the total exit at 4 hours and 5 hours together was 500 units, then the entry at
5 hours was:
a. 250 units
b. 300 units
c. 357 units
d. 420 units
Detailed solution: entry–exit ratio line graph question with options explained
This article provides a clear, step‑by‑step solution to an entry exit ratio line graph question, showing how to use given ratios and totals to find the correct entry value at 5 hours.
Understanding the question
The line graph shows the ratio of entry to exit of a molecule from a cell at each hour from 1 to 7 hours.
- At 4 hours, entry = 250 units.
- The total exit at 4 and 5 hours together = 500 units.
- From the graph, the entry/exit ratio values needed are:
- At 4 hours: ratio = 1.25
- At 5 hours: ratio = 1.40
Let:
E4= entry at 4 h = 250 unitsX4= exit at 4 hE5= entry at 5 h (unknown)X5= exit at 5 h
Step‑by‑step calculation
Entry/exit ratio at 4 h is 1.25, so:
E4 / X4 = 1.25250 / 1.25 = 200 unitsX4 = 200 units
Given total exit at 4 and 5 hours together is 500 units:
X4 + X5 = 500200 + X5 = 500X5 = 300 units
Entry/exit ratio at 5 h is 1.40, so:
E5 / X5 = 1.40E5 = 1.40 × 300 = 420 unitsHence, entry at 5 hours is 420 units.
The entry at 5 hours is 420 units, so option (d) is correct.
Explanation of each option
- (a) 250 units
This is the entry at 4 hours, not at 5 hours, so this confuses the given data with the required value. - (b) 300 units
300 units is the exit at 5 hours (found from the total exit condition), not the entry, so this is incorrect. - (c) 357 units
This does not satisfy the ratio at 5 hours, because357/300 = 1.19, not 1.40, so it contradicts the graph. - (d) 420 units
This satisfies both the entry/exit ratio at 5 hours (420/300 = 1.40) and the total exit condition, so this is the correct answer.


