16. Four different mutant lines showing similar phenotype were identified from a genetic screen. When genetic crosses among these mutants were carried out, the first mutant was found to complement the second, third and lines. However, no other fourth mutant complementation groups do the four mutant lines belongs to? (1) 1 (2) 2 (3) 3 (4) 4

Determining the number of complementation groups from mutant crosses

15. When two mutants having the same phenotype were crossed, the progeny obtained showed a wild-type phenotype. Thus the mutations are (1) non-allelic. (2) allelic. (3) segregating from each other. (4) independently assorting

Interpretation of wild-type progeny from crossing two mutants with the same phenotype

14. Two mutants of Drosophila melanogaster. one showing light red eye colour and the other showing dark brown eye colour, were crossed. In F1 all flies showed normal red eye colour. This indicated that the two mutations are (1) allelic. (2) non allelic. (3) linked. (4) unlinked.

Why light‑red and dark‑brown eye mutants give wild‑type F₁ in Drosophila

13. A cis-trans complementation test is carried out to identify (1) if two mutations are allelic in nature. (2) if two genes interact with one another. (3) the number of genes influencing phenotype. (4) to understand the dominance / recessjve relationships between alleles.

What does a cis–trans complementation test identify?

12. A fly with apricot coloured eye was crossed With a septa eyed fly of opposite sex. In Fl all flies were Wild tvpe. The genes responsible for the two (1) allelic (2) nonallelic (3) pseudo-allelic (4) paralogous genes

Complementation between apricot and sepia eye mutants in Drosophila

11. In a heterozygous two recessive mutation at different site will give mutant phenotype when genes involved are (1) Allelic and placed in cis (2) Allelic and placed in trans (3) Non-allelic and placed in cis (4) Non-allelic and placed in trans

When do two recessive mutations in a heterozygote still give a mutant phenotype?

10. Two different mutant of Drosophilla gives a mutant black body color. When these mutants are crossed all progeny have wild type color, It means mutation are (1) Codominant (2) Allelic (3) Non Allelic (4) Epistatic

Why two black-body mutants of Drosophila giving wild-type progeny are non‑allelic

9. In E. coli the complementation test is done by (1) Transformation (2) Obtaining merozygotes (3) Obtaining heterokaryons (4) Making them diploid

How is the complementation test performed in E. coli?

8. Mutation at two different loci of the same gene X results in altered functions. These two mutated versions of gene X are called (1) alleles (2) Complementation group (3) interrupted genes (4) linkage group

What are two different mutant versions of the same gene called?

7. A recessive inherited disease is expressed only in individuals of blood group O and not expressed in blood groups A, B or AB. Alleles controlling the disease and blood group are independently inherited. A normal woman with blood group A and her normal husband with blood group B already had one child with the disease. The woman is pregnant for second time. What is the probability that the second child will also have the disease? (1) 1/2 (2) 1/4 (3) 1/16 (4) 1/64

Probability that a second child has a recessive disease expressed only in blood group O

6. A newborn baby got mixed up with other babies in a hospital. If the mother is of O blood group and is Rh +veand the father is of AB blood group and is Rh -ve, which one of the following can be their baby? (1) AB and Rh +ve (2) O and Rh -ve (3) A and Rh +ve(4) B and Rh –ve

Which baby matches an O Rh+ mother and AB Rh– father?

5. The newborn baby of a mother having blood group AB, Rh+ and father having blood group O, Rh-, got mixed withother babies in the hospital. The baby with which of the following blood groups is expected to be of the said couple) (1) O, Rh+ (2) O, Rh- (3) AB, Rh-(4) B, Rh+

Which baby belongs to AB Rh+ mother and O Rh– father?

4. In a hospital three babies were mixed up. The blood group of the babies were A. B and AB. In order to identify the parents of the babies, the blood groups of the parents were determined. The results obtained were: Parent set 1 —A and AB Parent set 2 — AB and O Parent set 3— B and AB Which of the following conclusions can be definitively made? (1)The baby With blood group A is the child of the parent set 2. (2) The baby with blood group AB is the child of the parent set 1. (3) The baby with blood group B is the child of the parent set 3. (4) The parentage of none of the babies can be determined from the given information.

Can ABO blood groups alone identify parents when three babies are mixed up?

3. The ABO blood type tn human is under the control of autosomal multiple alleles. Colour blindness is recessive X-linked trait. A male with a blood type A and normal vision marries a female who also has blood type A and normal vision. The couple's first child a mate who is colour blind and has a blood group O. What is the probability that their next female child has normal vision and a blood group O? (1) 1/4 (2) 3/4 (3) 1/8 (4) 1

Probability that the next daughter is normal‑vision, blood group O

2. A mother of blood group O has a group A child. The father could be of blood type (1) A or B or O. (2) A only. (3) A or AB. (4) AB only.

Possible father blood groups when mother is O and child is A

1. Blood group tupe A antigen is a complex oligosaccharide which differs from H antigen present in type O individual by the presence of terminal (1) Glucose (2) Galactose (3) Fucose (4) N-acetyl galactosamine

Difference between blood group A antigen and H antigen in type O blood

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