9. Mutation in which subunit of RNA polymerase holoenzyme would have defect in correct initiation of transcription? (1) α subunit (2) β subunit (3) β' subunit (4) σ-subunit

9. Mutation in which subunit of RNA polymerase holoenzyme would have defect in correct initiation of transcription?
(1) α subunit                 (2) β subunit
(3) β’ subunit                (4) σ-subunit

Mutation in which subunit of RNA polymerase holoenzyme would result in a defect in the correct initiation of transcription?

  1. α subunit

  2. β subunit

  3. β′ subunit

  4. σ-subunit

Correct Answer: (4) σ-subunit

Explanation:

Structure of Prokaryotic RNA Polymerase Holoenzyme:

  • Core enzyme: α₂ββ′ω

  • Holoenzyme = Core enzyme + σ-subunit

Role of σ-subunit (Sigma Factor):

  • The σ-subunit is crucial for the initiation of transcription.

  • It guides the core RNA polymerase to the specific promoter sequences (−35 and −10 regions).

  • Without the σ-subunit, the polymerase cannot recognize the promoter → initiation fails.

  • Once transcription starts, the σ-factor usually dissociates from the complex.

Why Other Options Are Incorrect:

Subunit Function Role in Initiation
α Enzyme assembly & promoter interaction support Not directly responsible for promoter recognition
β Catalysis of RNA chain elongation Core enzymatic function, not initiation
β′ DNA binding and clamp function Structural, but not specific to initiation
Core Enzyme Subunits:
  • α subunit:
    Two copies (αI and αII) of this subunit are involved in the assembly of the core RNA polymerase enzyme and contribute to promoter recognition.
  • β subunit:
    This is the second largest subunit and forms part of the active catalytic site responsible for RNA synthesis.
  • β’ subunit:
    This is the largest subunit and also contributes to the active catalytic site, essential for RNA polymerization.
  • ω subunit:
    This is the smallest subunit and facilitates the assembly of the RNA polymerase enzyme. 

Transcription Initiation Factors (e.g., Sigma Factor):
  • Sigma factor (σ):
    This factor is crucial for recognizing specific promoter sequences on the DNA template, directing the binding of the core enzyme to the promoter, and initiating transcription. 

Conclusion:

  • The σ-subunit ensures that transcription begins at the right site by recognizing the promoter.

  • Mutation in this subunit → transcription initiation failure.

CSIR NET Takeaway:

  • Know the roles of RNA polymerase subunits:

    • σ-subunit = promoter recognition

    • β & β′ = catalytic core

    • α = structural and regulatory support

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  • Expert-led classes on RNA polymerase structure and function

  •  Practice with PYQs and mock tests focused on transcription regulation

  • Access PDF notes and video solutions on prokaryotic gene expression

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14 Comments
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    May 28, 2025

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    May 28, 2025

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    May 28, 2025

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    May 28, 2025

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    May 28, 2025

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    May 28, 2025

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    May 28, 2025

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    May 28, 2025

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    May 28, 2025

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    May 29, 2025

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    May 29, 2025

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    May 29, 2025

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    May 29, 2025

    Done sir ji 👍

  • Shreeji Charan
    June 1, 2025

    👍

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