(SEPT 2022-1) 34. A student was asked to plot a graph representing enzyme kinetic data for initial velocity, vO , and substrate concentration [S] using any of the equations given below. The student used an equation for which neither X-axis nor Y-axis had independent variables. Which one of the following equation might the student have used? (1) 1/ vO = (Km/Vmax) 1/[S]+ 1/Vmax) (2) [S]/vO = [S]/Vmaxx + (Km /Vmax) (3) vO / [S] = (Vmax / Km) - vO / Km (4) vO = V max [S] / Km + [S]

(SEPT 2022-1)
34. A student was asked to plot a graph representing enzyme kinetic data for initial velocity, vO , and substrate concentration [S] using any of the equations given below. The student used an equation for which neither X-axis nor Y-axis had independent variables. Which one of the
following equation might the student have used?
(1) 1/ vO = (Km/Vmax) 1/[S]+ 1/Vmax)
(2) [S]/vO = [S]/Vmaxx + (Km /Vmax)
(3) vO / [S] = (Vmax / Km) – vO / Km
(4) vO = V max [S] / Km + [S]

 

The correct answer is (3) v0[S]=VmaxKm−v0Km.


Introduction

Enzyme kinetics often involves transforming variables to linearize the Michaelis-Menten equation for easier extraction of kinetic constants. In some cases, the chosen equations produce plots where neither the x-axis nor y-axis is fully independent, meaning both variables share dependent components. Identifying such cases helps avoid misinterpretations and selects suitable plotting strategies. This article explains which enzyme kinetic equation produces a plot without independent variables on either axis, emphasizing its formation and utility.


The Equations and Their Variables

The four given equations for enzyme kinetics involve initial velocity v0, substrate concentration [S], and constants Vmax and Km:

  1. Lineweaver-Burk equation:

1v0=KmVmax1[S]+1Vmax

  • X-axis: 1[S] (independent)

  • Y-axis: 1v0 (dependent)

  1. Hanes-Woolf equation:

[S]v0=[S]Vmax+KmVmax

  • X-axis: [S] (independent)

  • Y-axis: [S]v0 (dependent)

  1. Eadie-Hofstee type rearrangement:

v0[S]=VmaxKm−v0Km

  • X-axis: v0 (dependent variable)

  • Y-axis: v0[S] (dependent variable)

Both axes depend on v0, so neither axis contains an independent variable.

  1. Michaelis-Menten original equation:

v0=Vmax[S]Km+[S]

  • X-axis: [S] (independent)

  • Y-axis: v0 (dependent)


Why Does Equation (3) Fit the Criteria?

  • Both axes in equation (3) depend on v0.

  • This dependence means the student using equation (3) plots a graph where neither axis is independently controlled.

  • Such plots are also called ratio plots and are useful in certain kinetic analyses but have unique interpretative traits.


Significance of Equation (3) in Enzyme Kinetics

  • Rearranged form of the Michaelis-Menten equation.

  • Useful in Eadie-Hofstee plots, where velocity is plotted against velocity normalized by substrate concentration.

  • Provides a linear plot from which Km and Vmax can be derived.


Summary Table of Plot Types

Equation Number Plot Variables (X-axis, Y-axis) Independent Variable on Axis? Common Usage
1 1/[S]1/v0 X-axis only Lineweaver-Burk plot
2 [S][S]/v0 X-axis only Hanes-Woolf plot
3 v0v0/[S] None Eadie-Hofstee plot
4 [S]v0 X-axis only Michaelis-Menten standard

Conclusion

Among the provided equations, only equation (3)—v0[S]=VmaxKm−v0Km—yields a plot where neither the X nor Y axis represents an independent variable, hence fitting the student’s scenario. This plot type facilitates enzyme kinetics analysis but requires careful interpretation due to both variables’ interdependence.

23 Comments
  • Aakansha sharma Sharma
    September 12, 2025

    The correct answer is (3) v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0. Bez it depends on variable it is Eadie hofstee plot

  • Varsha Tatla
    September 13, 2025

    Option 3rd gives correct explanation

  • Khushi Vaishnav
    September 13, 2025

    v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0.

  • Kajal
    September 14, 2025

    Option c is correct as here both the x and y axis have dependent variables

  • Sakshi yadav
    September 14, 2025

    v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0.

  • Pooja
    September 14, 2025

    Option c is correct answer

  • Kanica Sunwalka
    September 14, 2025

    ANS 3 is correct

  • Rishita
    September 14, 2025

    v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0

  • Santosh Saini
    September 14, 2025

    Correct answer is option 3

  • Bhawna Choudhary
    September 14, 2025

    Option 3 is correct answer

  • Manisha choudhary
    September 14, 2025

    Option 3 is correct

  • Anurag Giri
    September 15, 2025

    The correct answer is (3) v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0. Bez it depends on variable it is Eadie hofstee plot

  • Nilofar Khan
    September 15, 2025

    Correct answer is c
    Vo/[s] = Vmax/Km – Vo/km

  • Payal Gaur
    September 15, 2025

    C. Vo/S=VmX/km-Vo/Km

  • Mansukh Kapoor
    September 15, 2025

    The correct answer is option 3rd
    Because in this there is no independent variables in x -axis and y-axis

  • Pallavi Ghangas
    September 15, 2025

    3

  • Kirti Agarwal
    September 15, 2025

    Opt 3

  • Anjana sharma
    September 16, 2025

    v0=Vmax[S]Km+[S]v0=Km+[S]Vmax[S]

  • Palak Sharma
    September 16, 2025

    3

  • Palak Sharma
    September 16, 2025

    eadie hofstee type rearrangement

  • Muskan Yadav
    September 17, 2025

    v0[S]=VmaxKm−v0Km[S]v0=KmVmax−Kmv0. Eadie-Hofstee plot is shown

  • Minal Sethi
    September 18, 2025

    option 3 Eadie Hofstee equation

  • Deepika sheoran
    September 18, 2025

    Option 3 rd is correct
    Vo/S =Vmax/Km-Vo/Km

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