(JUNE 2010)
27. Km for enzyme is equal to where
(1) V0=Vmax (2) 2V0= Vmax
(3) 4V0=Vmax (4) V0 = 2 Vmax
The correct answer is (2)
Introduction
In enzymatic reactions, the initial reaction velocity (V0) depends on substrate concentration, enzyme affinity, and catalytic efficiency. The Michaelis constant (Km) is a critical parameter defined as the substrate concentration at which the enzyme-catalyzed reaction reaches half of its maximum velocity (Vmax). This concept is fundamental in biochemistry and enzymology, helping in characterizing enzyme behavior and substrate affinity. This article explains why the substrate concentration corresponding to V0=12Vmax equals Km with detailed biochemical foundations.
Michaelis-Menten Equation
The Michaelis-Menten equation expresses the initial velocity V0 as a function of substrate concentration [S]:
V0=Vmax[S]Km+[S]
Where:
-
V0 = Initial velocity
-
Vmax = Maximum velocity when enzyme is saturated
-
Km = Michaelis constant, substrate concentration at half maximal velocity
Derivation of Substrate Concentration at Half Vmax
Set V0=12Vmax:
12Vmax=Vmax[S]Km+[S]
Divide both sides by Vmax:
12=[S]Km+[S]
Cross multiplying:
Km+[S]=2[S]
Rearranged for [S]:
Km=[S]
This confirms that the substrate concentration at half-maximal velocity equals Km.
Significance of Km
-
Km reflects the enzyme’s affinity for the substrate; lower Km means higher affinity.
-
It allows prediction of enzyme activity under varying substrate levels.
-
Helps in understanding enzyme behavior in metabolic pathways and drug interactions.
Practical Use of Km in Enzyme Assays
-
Knowing Km helps set substrate concentration for optimal enzyme assay conditions.
-
Ensures accurate and reproducible measurement of enzyme activity.
-
Enables comparison between enzyme variants or inhibitors.
Summary Table
| Parameter | Definition | Importance |
|---|---|---|
| Michaelis constant Km | Substrate concentration at half-max velocity | Indicates enzyme-substrate affinity |
| Initial velocity V0 at [S]=Km | V0=12Vmax | Defines Km experimentally |
Conclusion
The Michaelis constant (Km) corresponds to the substrate concentration at which an enzyme-catalyzed reaction proceeds at half its maximum velocity. This critical relationship underpins enzyme kinetics studies and informs biochemical assays, drug development, and metabolic regulation.
This thorough elucidation equips students and researchers with a fundamental understanding of enzyme-substrate dynamics critical for success in biochemistry and molecular biology exams and research.



49 Comments
Aakansha sharma Sharma
September 12, 20252Vo=Vmax is answer
Varsha Tatla
September 12, 20252Vo=Vmax
Priya dhakad
September 12, 2025The correct option is 2Vo=Vmax
Dharmpal Swami
September 13, 2025Km =1/2 Vmax.
Sakshi yadav
September 13, 2025Km=1/2vmav
Sakshi yadav
September 13, 2025Km=1/2vmax
Mansukh Kapoor
September 13, 2025The correct answer is option 2nd
2V°=Vmax
Khushi Vaishnav
September 13, 20252Vo=Vmax
Kanica Sunwalka
September 13, 2025Km = 1/2 of Vmax
Sakshi Kanwar
September 13, 2025At km Vo is equals to 1/2 of vmax then can be written as 2Vo = Vmax
Mohd juber Ali
September 14, 20252V=Vmax
V=Vmax/2
Km=Vmax/2
Option 2 is right
Kajal
September 14, 2025Option b is correct bcz at km v is equal to half of maximum velocity
Aafreen Khan
September 14, 2025At Km V is the 1/2 of Vmax
So the 2Vo= Vmax
Soniya Shekhawat
September 14, 2025Km that which Vo is equals to 1/2 of vmax so also write in 2Vo = Vmax
Bhawna Choudhary
September 14, 20252V0= vmax
Pooja
September 14, 2025Km = 1/2vmax
Kirti Agarwal
September 14, 20252V0= Vmax
Payal Gaur
September 14, 2025Option B. 2V =Vmax
V = Vmax/2 (Km is half of maximum velocity )
Tanvi Panwar
September 14, 20252Vo = Vmax.
Anurag Giri
September 14, 2025At km Vo is equals to 1/2 of vmax then can be written as 2Vo = Vmax
Khushi Agarwal
September 14, 2025Option b is correct answer
Km for enzyme is equal to 2V0= Vmax
Neha Yadav
September 14, 2025At km Vo is equals to 1/2 of vmax then can be written as 2 Vo = Vmax
Anju
September 14, 2025Ans: 2vo= v max
Rishita
September 14, 20252 opt is Right
Santosh Saini
September 14, 2025At Vo is equal to 1/2 pf Vmax, then 2Vo=vmax
Anjali
September 14, 2025Km=1/2vmax
Vanshika Sharma
September 14, 2025V max/2
Avni
September 14, 20252Vo= V max
Ayush Dubey
September 14, 20252V0= Vmax
anjani sharma
September 14, 20252V0= Vmax
Pallavi Ghangas
September 14, 20252
Nilofar Khan
September 15, 2025Correct answer is (2) 2Vo = Vmax.
the initial reaction velocity (V0) depends on substrate concentration.
Mitali saini
September 15, 2025The correct answer is (2)2Vo = Vmax.
the initial reaction velocity (V0) depends on substrate concentration.
yashika
September 15, 2025The inititial reaction velocity depend on vel conc
Priyanshi sharma
September 15, 2025The correct answer is 2V0=Vmax
Asha Gurzzar
September 15, 2025Option 2is correct
Muskan singodiya
September 15, 20252Vo=Vmax
Simran Saini
September 15, 20252Vo = Vmax
Arushi Saini
September 15, 2025Option 2
2Vo = Vmax
Anjana sharma
September 16, 20252V0= Vmax
Sonal nagar
September 16, 2025Option 2
2V0= Vmax
Manisha gujar 2
September 16, 20252 is correct
Minal Sethi
September 16, 2025Km is where v = Vmax/2
Palak Sharma
September 16, 2025At Km V is the 1/2 of Vmax
So the 2Vo= Vmax
Alec
September 16, 20252Vo = Vmax is the correct ans.
Muskan Yadav
September 17, 20252Vo = Vmax is the correct option .
Ruchika
September 17, 2025Km=1/2vmax
Deepika sheoran
September 18, 2025Km = 1/2 max
2V0 = Vmax
Khushi Singh
September 25, 20252 is correct