Done sir

The primary role of RNase H is to degrade the RNA part of the RNA-DNA intermediate therefore it will shorten some strands in our experiment and we’ll observe what is given in option B and C

In above experiment is clearly see that in first set in which rnaseH is degard part of RNA in RNA and DNA hybrid if RNA is remove so then short fragment of DNA are produced which is the easily and fastly migrate in a page but in second set rnaseH H is absent in which RNA DNA hybrid is not cut so long fragment so slowly migrate so that’s why option are show in B and C

Correct option is option (2)
In set 1
RNase H removes RNA primers resulting in pure DNA fragments . These DNA fragments length became shorter , by this their molecular weight will be low they migrated faster. in comparison of set (2) in which RNAse H activity is absent

Rnase H remove rna primer .in first set rna is removed so only pure dna and its moleculer weight is less then set 2 set 1 is migrate fast and set 2 migrate slow bcz it have dna with rna primer so mw is more

Option B and C is correct
Because in the difference in their size of bands

Correct option is 2. RNase H is involved in degradation of RNA primer during eukaryotic replication. In case 1- RNase H removes primer which makes the DNA fragments short and light so it migrates faster while in case 2 the DNA remains heavy so it migrates slowly. Therefore there is difference in their mobility.

b and c

Correct answer: (2) b and c
Rnase H degrade RNA strand from set 1 which made it more lighter and faster in electrophoresis while in set 2 rna primer is present ,making strand heavier and slow moving .
That’s an easy one .
Suraj sir made it super easy by explaining banding pattern and bcz of that I got correct answer within 30 sec.

Option 2 is correct: because RNase H removes RNA primers from DNA fragments, resulting in smaller, faster-migrating DNA , Without RNase H, RNA-DNA hybrids remain, causing slower migration. Therefore, difference in mobility is observed

Option b is right bcz in set -1 Rnase H remove the primer ~ pure Dna fragments ~ faster migration but set 2 without Rnase H not remove primar producing rna – dna fragments larger and defferent ~ slow migration

Yes,the rna will degrade the primers so ,lenght will be shortened,and set 1 fragments are more mobile then set 2

2-👍

2. B and C RNase H present -pure DNA fragments and faster migration because remove rna primer by RNase H enzyme

Answer is b and c bcz set 1 m rnase H present degradation of RNA primer form dna fragment than fast migration set 2 m rnase activity not present showly migration

treatment with RNase H removes RNA primers from DNA fragments, resulting in smaller, faster-migrating DNA products.
Without RNase H, RNA-DNA hybrids remain, causing slower migration

Rnase H degrade rna-dna interaction

Rnase H removed rna primer form set 1 that makes dna smaller leading to fast migration .
In set 2 no Rnase H added so rna primer remain associated to newly synthesized dna leading to slower migration
So option 2 (b&c ) is correct

Set 1 Rna H removes Rna primers resulting in pure DNA fragments
Their molecular weight will be low they migrated fast.set 2 Rnase H Activity is Absent.

RNase H degrades dna rna in rna dna hybrid
When rna remove from hybrid then only pure dna obtain so ,in 1st set rna migrate faster then set b bcz set b RNase H less

RNase H degrades dna
rna in rna dna hybrid
When rna remove from hybrid then only pure dna obtain so ,in 1st set rna migrate faster then set b bcz set b RNase H less

B and C

Set 1 (with RNase H):
In set 1. RNase H removes RNA primers from RNA-DNA hybrids, resulting in pure DNA fragments without RNA segments. These DNA fragments are shorter and more uniform, leading to faster migration on the gel due to smaller size and more compact structure. Set 2 RNA primers remain attached to the newly synthesized DNA, producing RNA-DNA hybrid fragments that are larger and structurally different, causing slower migration on the gel so option B and C is correct

RNase H treatment changes fragment composition, resulting in different migration patterns
Removal of RNA primers produces smaller DNA fragments that migrate faster
Hence B and C are correct answer

If rnase h is present attached rna primers will be removed and migration of that dna will be fast

RNA H present pure DNA fragments and faster migration because remove RNA primer by Rnase H enzyme.