30. How many genetically different gametes can be made by an individual of genotype AaBbccDDEe?
(1) 3        (2) 5
(3) 1/4     (4) 32

Step-by-step reasoning

Genotype: Aa Bb cc DD Ee

• A locus: Aa → 2 possible alleles in gametes (A or a)
• B locus: Bb → 2 possible alleles (B or b)
• C locus: cc → 1 allele (c only)
• D locus: DD → 1 allele (D only)
• E locus: Ee → 2 possible alleles (E or e)

Heterozygous loci count

Number of heterozygous pairs (n) = 3 (A, B, E) [web:50][web:51].

For independently assorting loci, number of different gametes:

de>No. of gametes = 2ⁿ = 2³ = 8

So the true theoretical answer is 8 different gamete types [web:52].

Options analysis

• 32 corresponds to 2⁵ (five heterozygous loci, which is not the case here)
• 3 or 5 are not powers of 2
• 1/4 is not even a count

Given the standard genetics rule, the correct count from AaBbccDDEe is 8, but since 8 is absent from the MCQ options, this appears to be a misprint in the choices.