(DEC 2018) 67. For a reversible non-competitive inhibition of an enzyme, choose the plot that you would use to determine Km: _______ No inhibitor - - - - - - + Inhibitor

The correct answer is (1).


Introduction

Enzyme inhibition is a cornerstone of biochemistry and pharmacology, and visualizing its effects on kinetic parameters is essential. The Lineweaver-Burk double reciprocal plot provides a clear way to distinguish between competitive, non-competitive, and uncompetitive inhibition based on their effects on Vmax and Km. In reversible non-competitive inhibition, the x-intercept—used for determining Km—remains unchanged, even though the slope and y-intercept change. This article explains how to use the correct plot to determine Km in the presence of reversible non-competitive inhibitors.


Basis of Non-Competitive Inhibition

  • Non-competitive inhibitors bind to sites other than the active site, affecting enzyme activity regardless of substrate concentration.

  • This mechanism lowers Vmax but does not alter Km (enzyme’s affinity for substrate remains the same).

  • The effect can be visualized using the Lineweaver-Burk plot (1/V vs. 1/[S]), which linearizes Michaelis-Menten kinetics.


Lineweaver-Burk Plot Features in Non-Competitive Inhibition

  • y-intercept (1/Vmax) increases: Indicates decrease in Vmax.

  • x-intercept (−1/Km) remains the same: Indicates Km is unchanged.

  • Both inhibitor and no-inhibitor lines intersect the x-axis at the same point.

  • The slopes differ due to the decrease in Vmax.


Correct Plot Identification

  • In the provided images:

    • Plot (1) shows two lines (with and without inhibitor) intersecting at the same x-intercept (−1/Km), but with different slopes and y-intercepts.

    • This matches the textbook case for reversible non-competitive inhibition.


Why Other Plots Are Incorrect

  • Plot (2): Lines have different x-intercepts—indicative of competitive inhibition, not non-competitive.

  • Plot (3) and (4): Do not reflect the unchanged x-intercept which is unique to non-competitive inhibition.


Summary Table: Lineweaver-Burk Changes

Inhibition Type Change in y-intercept Change in x-intercept Best Plot
Non-competitive Increases Unchanged Plot (1)
Competitive Unchanged Increases Plot (2)
Uncompetitive Increases Decreases Plot (3)/(4)

Conclusion

In reversible non-competitive enzyme inhibition, the Lineweaver-Burk plot for Km determination is identified by the unchanged x-intercept regardless of the presence of inhibitor. This is represented by plot (1), where both lines intersect the x-axis at the same position.

34 Comments
  • Kirti Agarwal
    September 12, 2025

    Graph a

  • yashika
    September 12, 2025

    Unchanged x intercept

  • Bharti yadav
    September 13, 2025

    Graph A

  • Kanica Sunwalka
    September 13, 2025

    y intercept – increases
    x intercept – remains the same

  • Aakansha sharma Sharma
    September 13, 2025

    Correct answer is 3

  • Rishita
    September 14, 2025

    Graph a

  • Pratibha Jain
    September 14, 2025

    The correct answer is option (1).

  • Anju
    September 14, 2025

    Ans :1

  • Santosh Saini
    September 14, 2025

    Correct answer is 3 because in non competitive inhibition, the Vmax decreases and Km stay constant

  • Tanvi Panwar
    September 14, 2025

    option 3rd is the correct answer because in non competitive inhibition km remains the same so is 1/Km and Vmax. decreases bcz the inhibitor binds at site other than active site so it does not have any effect of substrate concentration. the line will intersect at the same point on X- axis bt at different points on Y-axis.

  • Dharmpal Swami
    September 14, 2025

    Write answer 1

  • Dharmpal Swami
    September 14, 2025

    Write answer 3

  • Pooja
    September 14, 2025

    A is correct

  • anjani sharma
    September 14, 2025

    Answer 3
    As in the non competitive inhibition the vmax on the yaxis is reduced and km on the x axis is same for all the inhibitor and non inhibitor

  • Pallavi Ghangas
    September 14, 2025

    1st graph is right

  • Palak Sharma
    September 14, 2025

    Correct answer is 3 because in non competitive inhibition, the Vmax decreases but Km remains constant.

  • Ankita Pareek
    September 14, 2025

    For non competative inhibition km remain the same intercect at the same point so that grap third is correct

  • Priya dhakad
    September 14, 2025

    The correct option is 3rd In non competitive inhibition the vmax decrease but km is constant .

  • Sakshi Kanwar
    September 14, 2025

    lowers Vmax but does not alter Km

  • Soniya Shekhawat
    September 15, 2025

    1st option is correct.

  • Vanshika Sharma
    September 15, 2025

    Correct answer is 3

  • Mohd juber Ali
    September 15, 2025

    In non competative inhibition all 3 lines intersept at same point of x axis (1/km not alter) so option 3 is right

  • Aafreen Khan
    September 16, 2025

    Option 3rd is correct answer

  • Anjana sharma
    September 16, 2025

    Curve 1 is correct due to decrease in vmax x -intersecpt unchanged

  • Nilofar Khan
    September 16, 2025

    Correct answer is 3 becouse in noncompetitive inhibition Vmax decrease but km is unchanged. all three line intercept at same point

  • Lokesh Kumawat
    September 16, 2025

    Answer 3rd is correct ??

  • Khushi Agarwal
    September 17, 2025

    correct answer is (1).

  • Priya khandal
    September 17, 2025

    A is right

  • Avni
    September 17, 2025

    The correct answer is (1)

  • Minal Sethi
    September 19, 2025

    option 3
    in non-competitive inhibition km remains same but vmax decreases so 1/vmax increases

  • Muskan Yadav
    September 19, 2025

    Correct answer is 3 because in non competitive inhibition, the Vmax decreases but Km remains constant.

  • Kajal
    September 25, 2025

    Graph 1 is right

  • Sachin kant sharma
    September 29, 2025

    Option 3rd is correct Yes — I endorse Let’s Talk Academy as a very strong choice for your CSIR NET Life Science preparation, especially given that your preparation style (conceptual clarity + experimental-based studying + daily practice + CBT simulation) aligns with their method.

  • Varsha Tatla
    December 11, 2025

    Done

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