(FEB 2022-11)
31. What is the fold difference between v at [S] =Km and v at [S] = 1000 Km where v is the
initial velocity of an enzyme catalyzed reaction, [S] is substrate concentration and Km is the Michaelis constant?
(1) 1.998 (2) 1000
(3) 2.998 (4) 3.998
The correct answer is (1) 1.998.
Introduction
Michaelis-Menten kinetics describe the relationship between the initial velocity of an enzyme-catalyzed reaction and substrate concentration. A key question is how the initial velocity v0 changes when substrate concentration varies greatly relative to the Michaelis constant (Km). This article calculates the fold difference in initial velocity between substrate concentrations of Km and 1000×Km, providing insights into enzyme saturation kinetics and reaction efficiency.
Michaelis-Menten Equation Recap
v0=Vmax[S]Km+[S]
Where:
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v0 = initial velocity
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Vmax = maximum velocity
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[S] = substrate concentration
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Km = Michaelis constant
Step 1: Calculate v at [S]=Km
vKm=Vmax×KmKm+Km=Vmax×Km2Km=Vmax2
Initial velocity at substrate concentration Km is half maximal velocity.
Step 2: Calculate v at [S]=1000Km
v1000Km=Vmax×1000KmKm+1000Km=Vmax×1000Km1001Km=10001001Vmax
Initial velocity approaches Vmax but slightly less due to substrate not being infinitely saturating.
Step 3: Calculate Fold Difference
Fold difference=v1000KmvKm=10001001VmaxVmax2=10001001×2≈1.998
Interpretation
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Increasing substrate from Km to 1000Km nearly doubles initial velocity.
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Saturation kinetics cause diminishing returns beyond substrate concentration near Vmax.
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The fold difference being just under 2 shows that substrate concentration has to increase massively to fully saturate enzymes.
Practical Implications
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Understanding these relationships guides substrate concentration selection in enzyme assays.
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It elucidates enzyme efficiency limits; enzymes reach near-max velocity even at relatively moderate substrate concentrations.
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Useful for drug discovery and metabolic control analysis.
Summary Table
| Substrate Concentration | Initial Velocity v0 | Relative to Vmax |
|---|---|---|
| Km | 12Vmax | 0.5 |
| 1000Km | 10001001Vmax≈0.999Vmax | ≈ 1 |
Conclusion
In Michaelis-Menten kinetics, raising substrate concentration from Km to 1000Km approximately doubles the initial velocity from 50% to nearly 100% of Vmax, yielding a fold difference of about 1.998. This exemplifies the dramatic effect of enzyme saturation and is relevant for enzymology study and practical applications.



20 Comments
Aakansha sharma Sharma
September 12, 2025the fold difference between v at [S] =Km and v at [S] = 1000 Km
1) v at [S] =Km so we know Vo=VmaxS/Km+S so here S=Km
Vmax Km/Km+Km=Vmax/2
2)v at [S] = 1000 Km so here S=1000Km
Vmax1000Km/Km+1000Km=Vmax1000/1001
So we have to calculate Fold increase= S2/S1=Vmax1000/1001/Vmax/2= 2000/1001=1.998 is answer
Varsha Tatla
September 13, 2025Very 1st we calculate the V at S =km
#2 we calculate the V at S=1000km
Now we calculate -fold increase by s2÷s1
By this way we find answer is1.998
So,here option 1st will be correct answer
Mohd juber Ali
September 14, 2025(A). S=km
V = vmax .km/km+km
V = v max/2
(B). S = 1000km
V = Vmax.km /km +1000km
V = Vmax Km/1001Km
V= Vmax/1001km
# S2/S1
1000Vmax/1001km ✖️2km/Vmax
2000/1001 ~2
Kanica Sunwalka
September 14, 2025V at (S) = Km ……………………. let it be S1
V at (S) = 1000 Km …………….. let it be S2
by Vo = Vmax S/ Km + S
we cal the value
then divide S2 by S1 = > for fold increase
ans is 1.998
option 1 is correct
Kirti Agarwal
September 14, 20251.998
Anurag Giri
September 14, 2025Coorect ans is 1.998
Khushi Agarwal
September 14, 2025The correct answer is (1) 1.998
S1= vmax/2
S2= 1000vmax/1001
S2/S1 = 1000vmax/1001 * 2/ vmax = 1.998
Rishita
September 14, 20251.998.
Neha Yadav
September 14, 20251.998 ans
Tanvi Panwar
September 14, 2025V at s= Km = Vmax.km/2km=Vmax/2
V at s =1000km= Vmax.1000km/km=1000km=Vmax.1000/1001
so, fold increase is S2/S1= 1.998.
Payal Gaur
September 14, 20251.998
Pallavi Ghangas
September 14, 20251.998
Nilofar Khan
September 15, 2025Correct answer is 1.998
Ayush Dubey
September 15, 20251.998
Asha Gurzzar
September 15, 20251.998answer
Minal Sethi
September 16, 20251. S=km
V = vmax .km/km+km
V = v max/2
2. S = 1000km
V = Vmax.1000km /km +1000km
V = Vmax 1000Km/1001Km
V= 1000Vmax/1001
fold increase = S2/S1
1000Vmax/1001 * 2/Vmax
1.98
Palak Sharma
September 16, 2025The correct answer is (1) 1.998
V1= vmax/2
V2= 1000vmax/1001
V2/V1 = 1000vmax/1001 * 2/ vmax = 1.998
Arushi Saini
September 16, 2025The correct answer is (1) 1.998
S1= vmax/2
S2= 1000vmax/1001
S2/S1 = 1000vmax/1001 * 2/ vmax = 1.998
Muskan Yadav
September 17, 2025fold increase is S2/S1
The result is approximately 1.998, which is close to 2
Therefore, option 1 is the correct answer
Deepika sheoran
September 18, 20251.998