The correct answer is (3) A- iv, B- iii, C- ii, D- i.
Introduction
Enzyme kinetics is foundational for understanding biochemical reactions and enzyme activity. Properly identifying how various properties—such as specific activity, turnover number, Michaelis constant, and catalytic efficiency—relate to their mathematical expressions is an essential skill for students preparing for competitive exams or pursuing advanced biochemical research. This guide clarifies these connections using standardized column matching from examination formats.
Column Matching Explanation
Properties and Their Kinetic Expressions
Column X: Enzyme Properties
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A. Specific activity
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B. Turnover number
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C. Michaelis constant
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D. Catalytic efficiency
Column Y: Expressions
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i. kcat/Km
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ii. substrate concentration at which v=(Vmax)/2
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iii. Vmax/moles of enzyme
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iv. Vmax/protein concentration
Detailed Matching
A. Specific Activity — iv. Vmax/protein concentration
Specific activity refers to the enzyme’s activity per milligram of total protein, usually in terms of maximum velocity divided by protein concentration.
B. Turnover Number — iii. Vmax/moles of enzyme
Turnover number (kcat) is defined as the number of substrate molecules converted per enzyme molecule per unit time, mathematically given by the maximum velocity divided by moles of enzyme.
C. Michaelis Constant — ii. substrate concentration at which v=Vmax/2
Michaelis constant (Km) is the substrate concentration at which the enzyme works at half its maximum velocity.
D. Catalytic Efficiency — i. kcat/Km
Catalytic efficiency reflects both substrate affinity and turnover, given by the ratio of turnover number to Michaelis constant.
Table of Correct Matches
| Property | Expression |
|---|---|
| A. Specific activity | iv. Vmax/protein concentration |
| B. Turnover number | iii. Vmax/moles of enzyme |
| C. Michaelis constant | ii. Substrate conc. at half Vmax |
| D. Catalytic efficiency | i. kcat/Km |
Significance in Biochemistry
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Mastery of these matches enables students to interpret and analyze enzyme experiments, design new assays, and clarify enzyme mechanisms.
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Correct definitions promote clear communication in scientific writing and laboratory notation.
Conclusion
The accurate mapping of enzyme properties to kinetic expressions is:
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A — iv
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B — iii
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C — ii
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D — i
This match aligns with option (3) from the provided list. Understanding these connections is vital for both academic success and professional practice in biochemistry and life sciences.
44 Comments
Khushi Vaishnav
September 12, 2025Specific activities -Vmax/protein concentration
Turnover number -Vmax/moles of enzyme
Michaelis constant- Substrate conc. at v=Vmax/2
Catalytic efficiency – kcat/Km
Varsha Tatla
September 13, 2025Catalytic efficiency -kcat /km
Turnover no -vmax/moles of enz.
Specific activities -vmax/concentration
Meachelis constant -vmax/w or km
Aakansha sharma Sharma
September 13, 2025Specific activities -Vmax/protein concentration
Turnover number -Vmax/moles of enzyme
Michaelis constant- Substrate conc. at v=Vmax/2
Catalytic efficiency – kcat/Km
Kajal
September 14, 2025Option 3 is correct answer
Pratibha Jain
September 14, 2025correct answer is option (3)
A- iv, B- iii, C- ii, D- i.
Rishita
September 14, 2025Option 3
Mohd juber Ali
September 14, 2025Enzyme soecific activity = Vmax/protein concentration
Turnover no.( kcat) = vmax/mole enzyme
Michealis menten constant = Vmax/2
Aafreen Khan
September 14, 2025Option 3rd is correct answer
Kanica Sunwalka
September 14, 2025option 3 is correct ans
Anju
September 14, 2025Ans:3
Dharmpal Swami
September 14, 20253 option correct
Santosh Saini
September 14, 2025Enzymes specific activity=Vmax/ protein concentration , Turnover number=Vmax/moles of enzyme , Michaelis constant= substrate concentration V =Vmax/2 , Catalytic efficiency=Kcat/km
Pooja
September 14, 2025Option 3rd is correct
Soniya Shekhawat
September 14, 2025Option 3rd is correct
yashika
September 14, 2025Catalytic efficiency kcat /km
Konika Naval
September 14, 2025Option 3
Vanshika Sharma
September 14, 2025Opt 3 is correct
Sakshi Kanwar
September 14, 2025D = 1
A= 4
B= 3
C= 2
Kirti Agarwal
September 14, 2025Opt c
Muskan singodiya
September 14, 2025Specific activity -Vmax/protein con.
Turnover number -Vmax/moles of enzyme
Michalelis constant -sub.con. at which v=(Vmax)/2
Catalytic efficiency – Kcat/km
Sakshi yadav
September 14, 2025Option 3
Palak Sharma
September 14, 2025Specific activity = Vmax/protein concentration
Turnover number = Vmax/moles of enzyme
Michaelis constant= Substrate conc. at v=Vmax/2
Catalytic efficiency – kcat/Km
Priya dhakad
September 14, 2025Specific activities -Vmax/protein concentration
Turnover number -Vmax/moles of enzyme
Michaelis constant- Substrate conc. at v=Vmax/2
Catalytic efficiency – kcat/Km
Bhawna Choudhary
September 14, 2025Option 3 is correct answer
Deepika sheoran
September 15, 2025Specific activity = Vmax/Protein concentration.
Turnover number= Vmax/moles of enzyme.
Michaelis constant= Substrate concentration at which V=(Vmax)/2
Catalytic efficiency=Kcat/Km
Anurag Giri
September 15, 2025Enzyme soecific activity = Vmax/protein concentration
Turnover no.( kcat) = vmax/mole enzyme
Michealis menten constant = Vmax/2
Roopal Sharma
September 15, 2025Option 3
Nilofar Khan
September 15, 2025correct answer is (3)
A- iv, B- iii, C- ii, D- i.
A.Specific activities -Vmax/protein concentration
B.Turnover number -Vmax/moles of enzyme
C.Michaelis constant- Substrate conc. at v=Vmax/2
D.Catalytic efficiency – kcat/Km
Samiksha bajiya
September 15, 2025Option 3 is correct answer
Komal Sharma
November 1, 2025This match aligns with option (3) from the provided list. Understanding these connections is vital for both academic success and professional practice in biochemistry and life sciences.
Payal Gaur
September 15, 2025Option 3
Tanvi Panwar
September 15, 2025Option 3 is correct.
Anjana sharma
September 16, 2025Option 3rd is correct
Khushi Agarwal
September 16, 2025correct answer is (3) A- iv, B- iii, C- ii, D- 1
Sonal nagar
September 16, 2025Option 3
Simran Saini
September 16, 2025A- iv, B- iii, C- ii, D- i.
A.Specific activities -Vmax/protein concentration
B.Turnover number -Vmax/moles of enzyme
C.Michaelis constant- Substrate conc. at v=Vmax/2
D.Catalytic efficiency – kcat/Km
Payal Gaur
September 16, 2025Option 3rd
Specific activity – Vmax/protein concentration
Turnover number- Vmax/moles of enzyme
MM constant – Vmax /2
Catalytic efficiency- kcat/km
Avni
September 16, 2025Specific activity – Vmax/protein concentration
Turnover number – Vmax/moles of enzyme
Michaelis constant – Substrate conc. at half Vmax
Catalytic efficiency – kcat/Km
Ruchika
September 17, 2025Answer 3 is correct
Priya khandal
September 17, 2025Third is correct
Payal Solanki
September 18, 2025Option 3
Muskan Yadav
September 18, 2025A. Specific activity iv. VmaxVmax/protein concentration
B. Turnover number iii. VmaxVmax/moles of enzyme
C. Michaelis constant ii. Substrate conc. at half VmaxVmax
D. Catalytic efficiency i. kcat/Kmkcat/Km
3 RD option is correct.
Minal Sethi
September 19, 2025Specific activity – Vmax/protein concentration
Turnover number – Vmax/moles of enzyme
Michaelis constant – Substrate conc. at Vmax/2
Catalytic efficiency – kcat/Km
Komal Sharma
November 1, 2025Option 3rd is correct