(FEB 2022-1) 56. A schematic of a metabolic pathway is shown below. Under which of the following conditions would stoichiometric amounts of end products K and L be obtained if a concerted feedback inhibition mechanism were in operation? (1) K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L (2) D→E is inhibited at equal amounts of K and L; K inhibits F→H and L inhibits F→G (3) D→E is inhibited at equal amount of G and H; K inhibits F→H and L inhibits F→G (4) K inhibits F→H and L inhibits F→G

The correct answer is (1) K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.


Introduction

Metabolic pathways often branch to produce multiple end products, each with distinct cellular roles. To maintain cellular balance, these pathways are tightly regulated—one crucial mechanism is concerted feedback inhibition, where end products collectively modulate key steps, ensuring stoichiometric output. This article explores the logic and biochemical basis for achieving balanced end product formation using feedback inhibition, applying these concepts to a branched pathway schematic for advanced life science learners.


Pathway Layout and Branch Points

Given pathway:

  • D → E → F

  • F → G → I → K

  • F → H → J → L

End products: K and L, each formed via separate branches from the common intermediate F.


Principle of Concerted Feedback Inhibition

  • Concerted inhibition involves regulation by both end products.

  • The aim: prevent over-production of one branch’s product, secure equal (stoichiometric) formation.

  • Each product inhibits its branch and together they control the common upstream entry.


Correct Regulatory Logic

  • K inhibits F→G

    • This blocks excess K branch flux when K accumulates.

  • L inhibits F→H

    • This blocks excess L branch flux when L accumulates.

  • D→E inhibited at equal amounts of K and L

    • This ensures entry of substrate (D) is downregulated only when both products accumulate, enforcing stoichiometric output.


Why This Achieves Stoichiometric Output

  • If only K or L could inhibit the main entry, the pathway could produce an excess of one product if the other’s demand is low.

  • By inhibiting at F→G or F→H individually, each branch is self-regulated.

  • Only when both K and L build up is the initial entry (D→E) reduced—this ensures neither product is far in excess of the other.


Why Other Choices Are Incorrect

  • Option 2/3/4:

    • Suggest additional upstream branch inhibition or misplacement of regulatory points—not as efficient for enforcing strict stoichiometric (equal) end product formation.


Summary Table

Step Inhibited Triggered By Impact
F→G K accumulation Reduces K branch output
F→H L accumulation Reduces L branch output
D→E Equal K and L Reduces overall pathway input

Biological Significance

  • Maintains critical cellular ratios of products.

  • Protects cell against metabolic imbalance or wasteful excess of specific molecules.

  • Exemplifies elegant regulatory design in biochemistry.


Conclusion

Concerted feedback inhibition at key nodes ensures stoichiometric production of two pathway end products. In this schematic, K and L inhibit their respective branches, and together their combined build-up impedes pathway entry, maintaining equal product formation. Hence, option (1) correctly describes this balanced biochemical logic.

26 Comments
  • Khushi Vaishnav
    September 12, 2025

    K inhibits F➡️G and L inhibits F➡️H; D➡️E is inhibited at equal amounts of K and L.

  • Kanica Sunwalka
    September 13, 2025

    option 1st is correct
    k inhibiits f to g
    l inhibits f to h
    d to e is inhibited at equal amounts of k and l

  • Kajal
    September 13, 2025

    Option 1 is correct answer .

  • Aakansha sharma Sharma
    September 13, 2025

    The correct answer is (1) K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

  • Rishita
    September 14, 2025

    Done sir 👍🏻

  • Pratibha Jain
    September 14, 2025

    correct answer is option (1)
    K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

  • Mohd juber Ali
    September 14, 2025

    Correct option a

  • Santosh Saini
    September 14, 2025

    Correct answer is 1st

  • Dharmpal Swami
    September 14, 2025

    A is correct answer

  • yashika
    September 14, 2025

    Concreted feedback inhibition

  • Khushi Agarwal
    September 14, 2025

    The correct answer is A
    K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L

  • Konika Naval
    September 14, 2025

    K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

  • Soniya Shekhawat
    September 14, 2025

    Easy sir option 1st is right

  • Aafreen Khan
    September 14, 2025

    Option 1st is correct answer

  • Pallavi Ghangas
    September 14, 2025

    1

    • Bhawna Choudhary
      September 15, 2025

      (1) K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

  • Sakshi yadav
    September 14, 2025

    K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L

  • Palak Sharma
    September 14, 2025

    The correct answer is A
    K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L

  • Sakshi Kanwar
    September 14, 2025

    K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L. Making equal product formation

  • Anurag Giri
    September 15, 2025

    The correct answer is (1) K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

  • Tanvi Panwar
    September 16, 2025

    K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

  • Avni
    September 17, 2025

    The correct answer is (1) K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

  • Priya khandal
    September 17, 2025

    1st is right done ✅

  • Minal Sethi
    September 19, 2025

    option a

  • Muskan Yadav
    September 19, 2025

    K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

  • Kajal
    September 25, 2025

    The correct answer is (1) K inhibits F→G and L inhibits F→H; D→E is inhibited at equal amounts of K and L.

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