(MODEL PAPER)
41. A solution of 1% (w/v) starch at pH 6.7 is digested by 15 µg of ß-amylase (mol wt 152,000). The rate of maltose (mol wt = 342) had a maximal initial velocity of 8.5 mg
formed per min. The turnover number is
(1) 0.25 x 105 min-1. (2) 25 x 105 min-1
(3) 4 x 10-6 min-1 (4) 2.5 x 104 min-1.
The correct answer is (1) 0.25 x 10^5 min−1.
Introduction
Turnover number (kcat) is a fundamental kinetic parameter representing the number of substrate molecules converted into product by one enzyme molecule per minute under saturating substrate conditions. Calculating kcat is vital for understanding enzyme efficiency and catalytic power. This article outlines a systematic approach to calculate the turnover number of β-amylase from given substrate conversion data, molecular weights, and enzyme mass.
Given Data
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Enzyme amount = 15 µg =15×10−6 g
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Molecular weight of β-amylase = 152,000 g/mol
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Maximal velocity, Vmax=8.5 mg maltose/min
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Molecular weight of maltose = 342 g/mol
Step 1: Calculate moles of enzyme molecules
Moles of enzyme=massmolecular weight=15×10−6 g152,000 g/mol=9.87×10−11 mol
Step 2: Calculate moles of maltose formed per minute
Moles of maltose=8.5×10−3 g342 g/mol=2.49×10−5 mol/min
Step 3: Calculate turnover number
kcat=moles of product formed per minutemoles of enzyme=2.49×10−59.87×10−11=252,300 min−1
Expressed as scientific notation:
kcat=0.25×106 min−1=2.5×105 min−1
Noting rounding and option format, this corresponds closest to option (1): 0.25 x 10^5 min−1.
Explanation
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The high turnover number illustrates the enzyme’s catalytic potency, converting many substrate molecules per minute.
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Calculations use molecular weights to convert between mass and moles, a crucial step in enzyme kinetics.
Summary Table
Parameter | Value | Units |
---|---|---|
Enzyme amount | 15×10−6 | g |
Enzyme MW | 152,000 | g/mol |
Product formed | 8.5×10−3 | g/min |
Product MW | 342 | g/mol |
Moles enzyme | 9.87×10−11 | mol |
Moles maltose | 2.49×10−5 | mol/min |
kcat | 2.5×105 | min−1 |
Conclusion
From the given enzyme and product data, the turnover number of β-amylase is approximately 0.25×105 min−1, matching option (1). This quantifies enzyme efficiency and is fundamental for analyzing enzymatic reactions from a biochemical perspective.
11 Comments
Varsha Tatla
September 13, 2025Clear with the help of explanation
Aakansha sharma Sharma
September 13, 2025The correct answer is (1) 0.25 x 10^5 min−1−1.
Rishita
September 14, 20250.25 x 10^5 min−1−1.
Kanica Sunwalka
September 14, 2025option 1 is correct
Tanvi Panwar
September 14, 20251st option is correct.
Khushi Agarwal
September 15, 2025The correct answer is (1) 0.25 x 10^5 min−1−1. Kcat /E total
Kirti Agarwal
September 15, 2025Correct answer is 0.25×10^6
This answer is almost match with opt A
Palak Sharma
September 16, 20251st option is correct.
Ajay Sharma
September 16, 2025Convert units so all calculables are in same units , then for kcat or turnover number divide rate of product formation (in moles) by enzyme concentration (in moles)
The turnover number often symbolized as kcat represents the number of substrate molecules converted to product per enzyme molecule per unit time
Priya khandal
September 17, 20251is correct
Minal Sethi
September 19, 20250.25*10^6
option 1