(DEC 2019 ASSAM) 55. An allosteric enzyme has two heterotropic effectors, X and Y. The allosteric constant, L for the enzyme in the absence of effector molecules is 180. For the X- saturated form, the value of L increases from 180 to 1200, while for Y-saturated form it decreases to 60. What kind of effector molecules are X and Y? (1) X and Y both are positive regulators. (2) X is a negative regulator while Y is a positive regulator. (3) X is a positive regulator while Y is a negative regulator. (4) X and Y are not allosteric regulators.

(DEC 2019 ASSAM)
55. An allosteric enzyme has two heterotropic effectors, X and Y. The allosteric constant, L for the enzyme in the absence of effector molecules is 180. For the X- saturated form, the value of L increases from 180 to 1200, while for Y-saturated form it decreases to 60.
What kind of effector molecules are X and Y?
(1) X and Y both are positive regulators.
(2) X is a negative regulator while Y is a positive regulator.
(3) X is a positive regulator while Y is a negative regulator.
(4) X and Y are not allosteric regulators.

The correct answer is (2) X is a negative regulator while Y is a positive regulator.


Introduction

Allosteric enzymes undergo conformational changes upon effector binding, which modulates their activity. Effectors binding at regulatory sites can be positive regulators that enhance activity or negative regulators that inhibit activity. The allosteric constant L=[T]/[R] — the ratio of the tense (inactive) to relaxed (active) enzyme states — quantifies this regulation. Values of L reflect the equilibrium between inactive and active conformations, shifting in response to effectors.


Role of Allosteric Constant L

  • When L increases, the equilibrium favors the T (inactive) state, reducing enzyme activity.

  • When L decreases, the equilibrium favors the R (active) state, enhancing enzyme activity.


Interpreting the Given Data

  • Without effectors, L=180, indicating baseline inactive/active state distribution.

  • With effector X saturation, L increases to 1200 → equilibrium shifts toward inactive form → X is a negative regulator.

  • With effector Y saturation, L decreases to 60 → equilibrium shifts toward active form → Y is a positive regulator.


Why Other Options Are Incorrect

  • (1) Both positive regulators would both decrease L, not increase/decrease oppositely as shown.

  • (3) Reverse roles contradict observed L shifts.

  • (4) Clear changes in L confirm X and Y act as allosteric regulators.


Biological Significance

  • Positive and negative effectors allow precise control of enzyme activity in response to cellular needs.

  • This dynamic regulation maintains metabolic balance and responsiveness.


Summary Table

Effector Change in L Regulatory Role
X 180→1200 (increase) Negative regulator
Y 180→60 (decrease) Positive regulator

Conclusion

Effector X increases the allosteric constant L, promoting enzyme inactivity, marking it as a negative regulator. Effector Y decreases L, promoting enzyme activity, marking it as a positive regulator. Hence, option (2) is the correct answer.


This explanation clarifies the biochemical principles of allosteric regulation, aiding students and researchers in interpreting enzyme modulation mechanisms accurately.

28 Comments
  • Khushi Vaishnav
    September 12, 2025

    X is a negative regulator while Y is a positive regulator.

  • Kajal
    September 13, 2025

    Option 2 is correct as x is negative regulator while y is positive regulator ..

  • Kanica Sunwalka
    September 13, 2025

    When L increases – > enzyme activity decreases
    L decreases -> enzyme activity increases
    so here , effector X increases the value of L to 1200 => -ve regulator
    effector Y decreases the value of L to 60 => + ve regulator

    option 2 is correct

  • Aakansha sharma Sharma
    September 13, 2025

    When L increases – > enzyme activity decreases
    L decreases -> enzyme activity increases
    so here , effector X increases the value of L to 1200 => -ve regulator
    effector Y decreases the value of L to 60 => + ve regulator

  • Pratibha Jain
    September 14, 2025

    correct answer is option (2)
    X is a negative regulator while Y is a positive regulator.

  • Mohd juber Ali
    September 14, 2025

    X is negative regulators bcs Allosteric constant increase 180to 1200)favour t state(inactive
    Y is positive regulators bcz allosteric decrease (1200 to 60 )R state active

  • Santosh Saini
    September 14, 2025

    X is nagetive regulator while Y is positive regulator

  • Anju
    September 14, 2025

    L=180
    L inc-1200 towards in active (x-ve) regulator
    L decrease -60 shift towards active form(y+ve) regulator

  • Dharmpal Swami
    September 14, 2025

    X is a negative regulator and y is a positive regulator

  • yashika
    September 14, 2025

    C increase allosteric constant and become negative regulator and vice versa

  • Pooja
    September 14, 2025

    Option b is correct
    X is a negative regulator while Y is a positive regulator

  • Soniya Shekhawat
    September 14, 2025

    Allosteric constant is LLis increase then enzyme activity is decrease so X is processed 180 to 1200 means negative regulator and Y form is decrease LL that means increase enzymatic reaction that is positive regulator.

  • Aafreen Khan
    September 14, 2025

    X is a negative regulator while Y is a positive regulator because if allosteric constant LL increases then enzyme activity decreases
    In X the LL is increasing from 180-1200 then X is negative regulator and Y decreasing LL then it is positive regulator

  • Pallavi Ghangas
    September 14, 2025

    When Allosteric constant is more equilibrium favours in active enzymes reducing enzyme activity and when the constant value is less active enzymes are more more enzyme activity

  • Kirti Agarwal
    September 14, 2025

    X is negative Y is positive allosteric

  • Aartii sharma
    September 14, 2025

    X is positive y is positive allosteric

  • Palak Sharma
    September 14, 2025

    When L increases = enzyme activity decreases
    L decreases = enzyme activity increases
    so here , effector X increases the value of L to 1200 = -ve regulator
    effector Y decreases the value of L to 60 =+ ve regulator

    option 2

  • Deepika sheoran
    September 15, 2025

    Option 2nd correct
    X is negative regulator and y is positive regulator.

  • Roopal Sharma
    September 15, 2025

    When L increases enzyme activity decreases .
    When L decreases enzyme activity increases . X is negative regulator and Y is positive.

  • Parul
    September 15, 2025

    Effector X increases the Allosteric constant L means increasing the enzyme inactivity – so it is a Inhibitor.
    Effector Y decreases the allosteric constant L means increasing the enzymatic activity – so it is a activator.

  • Nilofar Khan
    September 16, 2025

    Correct answer is 2
    X is nagative regulator becouse L increase anzym activity decrease
    Y is positive regulator becouse L decreases anzym activity increases

  • Khushi Agarwal
    September 16, 2025

    The correct answer is (2) X is a negative regulator while Y is a positive regulator

  • Tanvi Panwar
    September 16, 2025

    X is a negative regulator bcz it inactivates the enzyme while Y is a positive regulator as it activates the enzyme.

  • Avni
    September 17, 2025

    The correct answer is (2) X is a negative regulator while Y is a positive regulator

  • Priti khandal
    September 17, 2025

    2is right

  • Minal Sethi
    September 19, 2025

    X is a negative regulator and Y is a positive regulator

  • Muskan Yadav
    September 19, 2025

    X is a negative regulator while Y is a positive regulator.

  • Kajal
    September 25, 2025

    The correct answer is (2) X is a negative regulator while Y is a positive regulator

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