In an invitro experiment using radio-labeled nucleotides, a researcher is trying to analyze the possible products or DNA replication by resolving the products using urea-polyacrylamide gel electrophoresis. In one experimental setup RNase-1 was added

(Set 1), while in another set no RNase II was added (Set 2) The possible observations of this experiment could be

Done

Done

Ok Sir

OK sir 👍

👍

Ok sir 👍🏻

Done sir

Ok Sir.. 🙌🙌

Nice 👍

👍👍

ok sir

👍👍

Done sir

👍✔️

👍🏻👍🏻

Faster migration of DNA fragments in Set 1 rather than set 2

Rnase cleave the primer then fragments are short in set 1 compair then set 2
So set1 are fast moving

Done sir

B option is correct, because rnase degrade newly synthesized rna and the 1st tube hybrid rna will move fast compare to second,and this cause difference in mobility of rna fragments

option b is correct
Rnase 1 cut the primer so mw in set1 is low than the 2nd set so by low MW the set 1 band is faster than set 2 and in mobility difference is shown

Done sir

Option b is correct
Because Rna leads to Faster migration of DNA fragments set 1 but Rna primer impact mobility in electrophoresis.

Done

Done sir 👍🏻

RNAse remove the primer from DNA which reduce the size of DNA and migration will be faster.

B option is correct

(b) 2 and 3
Set1 moves Faster than set 2

Newly synthesized DNA which have intact primers (no RNAase) moves slower than DNA without primers as cleaved by the RNAase.

Set 1 moves faster than set 2
Statement 2&3 are correct

Done sir

Statement 2 Nd 3 is correct

Set 1 me primer remove fragment chhota← faster migration
Set 2 me primer present → fragment bada ← slower migration.
Isliye dono sets me mobility me clear difference dikhega.
2 and 3 are correct answer

b) 2 and 3

Ans- B

Answer is d

2 and 3

RNAase will remove the RNA primer hence results in shorter DNA fragments in set 1 as in set 2 no RNAase is added so the RNA primer will remain attached hence results in larger fragments. And as we know that shorter fragments move faster than larger fragments in gel electrophoresis the fragments of set 1 will move faster than the fragments of set 2

Done

RNase I digestion leads to faster migration of DNA fragments in Set 1, confirming that RNA primers impact mobility in electrophoresis so option 2 and 3 r correct

Clear

(2) There is distinct difference in the mobility of the newly synthesized labeled DNA fragments between Set and Set 2
(3) The mobility of the newly synthesized labeled DNA fragments in case of Set 1 is faster as compared to the Set 2

In first tube RNase is added so degradation of dna occur result in faster migration and in second tube no RNase added so no degradation and result in slower migration

Good one sir 😊

Right answer 2&3

In 1st set RNase added so migration is fast compared to set 2nd because RNase is not present in set 2nd so degradation are not occur nd migration is slow. option b is correct.

correct ans. is option b – 2 and 3

Correct answer is option b.

Right answer B

Option b is correct

Answer b. 2nd 3 bcz in set 1 rna primers are degraded and set 2 rna primers remains attached

B

In set 1#primer removal part small it means fast migration
In set 2#primer removal part large it means slow migration .thus , diffrence clearly visible between both bands

Ok sir

Option B

Correct answer is option (b)
2 and 3 In 1st set RNase added so migration is fast compared to set 2nd because RNase is not present in set 2nd so degradation are not occur nd migration is slow

Faster migration of DNA fragments in Set 1 rather than set 2

B would be correct
Newly synthesized DNA which have intact primers (no RNAase) moves slower than DNA without primers as cleaved by the RNAase.

There is a distinct difference in mobility between set 1 and set 2 (correct option 2)
Set 1 . Rnase treated -DNA fragments will be shorter because RNA primers are removed.
Set 2. (No Rnase treatment)-DNA fragment will still have RNA primers attached , making them larger and affecting gel mobility.
The mobility of newly synthesized labeled dna fragments in set 1 is faster compared to set 2 (correct -option 3)
Smallar dna fragments move faster in polycrylamide gel . Since set 1 has RNA primers removed, the DNA fragments are smaller and migrate faster than those in set2.
In set 2 ,RNA primers make the fragments larger and more .

statement 2 and 3 are correct . set 2nd will move slower in comparison to set 1 because in set 2 RNA primers are attached making them heavy and hence they move slower.

RNase I digestion leads to faster migration of DNA fragments in Set 1, confirming that RNA primers impact mobility in electrophoresis so option 2 and 3 r correct

Because of rnase okazaki fragments will be removed in set 1 making it more mobile in gel

Option b

2 and 3 option is correct because Rnase 1 degrades the RNA strands in RNA DNA hybrid and in set 2 RNA primers remain attached to the newly synthesized dna fragments.

Done ✅

RNAase will remove the RNA primer hence results in shorter DNA fragments in set 1 as in set 2 no RNAase is added so the RNA primer will remain attached hence results in larger fragments. And as we know that shorter fragments move faster than larger fragments in gel electrophoresis the fragments of set 1 will move faster than the fragments of set 2

B option is correct