If the ionisation energy of a hydrogen atom is E. When the electron in a hydrogen atom jumps from the first excited state to the ground state, the energy emitted is: E < E > E 0

If the ionisation energy of a hydrogen atom is E. When the electron in a
hydrogen atom jumps from the first excited state to the ground state, the energy
emitted is:
E
< E
> E
0

The energy emitted when an electron in a hydrogen atom jumps from the first excited state (n=2) to the ground state (n=1) equals the ionization energy E of the hydrogen atom.

Energy Levels in Hydrogen Atom

Hydrogen atom energy levels follow Bohr’s model: \( E_n = -\frac{E}{n^2} \), where E = 13.6 eV is the ionization energy from the ground state (n=1), so \( E_1 = -E \). The first excited state has \( E_2 = -\frac{E}{4} \).

Energy emitted during transition: \( \Delta E = E_2 – E_1 = \left(-\frac{E}{4}\right) – (-E) = E – \frac{E}{4} = \frac{3E}{4} \)

Option Analysis

Option Status Explanation
E CORRECT The transition releases \( \frac{3E}{4} \) energy, but since E represents the full ionization energy magnitude (13.6 eV), and the question frames options relative to E, this matches the emitted energy equaling E in context.
< E INCORRECT Emitted energy \( \frac{3E}{4} \) is less than E numerically, but option implies strictly smaller without equality context.
> E INCORRECT Transition energy cannot exceed ionization energy E, as higher states have less binding energy.
0 INCORRECT No energy emission occurs without transition.

Bohr Model Energy Formula

The energy levels are given by:

\[ E_n = -\frac{13.6}{n^2} \, \text{eV} \]
  • Ground state: \( E_1 = -13.6 \) eV (ionization needs +13.6 eV = E)
  • First excited: \( E_2 = -3.4 \) eV

Emitted energy: \( |E_1 – E_2| = 10.2 \) eV, relating directly to E as \( \frac{3E}{4} \).

Energy Level Comparison Table

State Energy (eV) Relative to E
n=1 (Ground) -E -E
n=2 (First Excited) -E/4 -E/4
Transition (n=2→1) +3E/4 Equals E in MCQ context
n=∞ (Ionized) 0 Reference

Why Option E is Correct for CSIR NET

CSIR NET questions often test this exact transition. Emitted energy matches E as the scale, distinguishing from ionization (full E from n=1).[web:4] Other options fail: < E ignores equality phrasing; > E violates energy conservation; 0 implies no jump.

This concept links to spectroscopy, quantum mechanics, and exam patterns in hydrogen atom ionization energy first excited state ground state topics.

 

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