(JUNE 2018) 36. The Vmax and Km from a Lineweaver-Burk plot of an enzyme reaction where 1/v = 40µM-1 min at 1/[S] = 0 and 1/[S] = -1.5 x 102 mM-1 at 1/v = 0 are (1) 0.025 µM min-1 and 0.67 x 10-2mM (2) 0.025 µM-1 min and 0.67 x 10-2 (3) 0.025 µM min-1 and 1.5 x 102 mM-1 (4) 0.038 µM min-1 and 0.67 x 10-2mM

(JUNE 2018)
36. The Vmax and Km from a Lineweaver-Burk plot of an enzyme reaction where 1/v = 40µM-1
min at 1/[S] = 0 and 1/[S] = -1.5 x 102 mM-1 at 1/v = 0 are
(1) 0.025 µM min-1 and 0.67 x 10-2mM
(2) 0.025 µM-1 min and 0.67 x 10-2
(3) 0.025 µM min-1 and 1.5 x 102 mM-1
(4) 0.038 µM min-1 and 0.67 x 10-2mM

The correct answer is (1) 0.025 µM min−1 and 0.67 \times 10^{-2}$$ mM.


Introduction

The Lineweaver-Burk plot, a double reciprocal graph of the Michaelis-Menten equation, is a classical method used to estimate kinetic parameters such as maximum velocity Vmax and Michaelis constant Km of enzyme reactions. Given intercepts from the plot, these parameters can be calculated directly. This article clarifies how to derive Vmax and Km given specific plot intercepts, tailored for academic rigor and practical enzyme kinetics understanding.


Given Data from the Lineweaver-Burk Plot

  • 1/v=40 μM−1 min at 1/[S]=0 (Y-intercept)

  • 1/[S]=−1.5×102 mM−1 at 1/v=0 (X-intercept)


Understanding the Lineweaver-Burk Equation

The Lineweaver-Burk plot plots 1v against 1[S]. The equation is:

1v=KmVmax1[S]+1Vmax

  • Y-intercept =1Vmax

  • X-intercept =−1Km


Calculation of Vmax

From the Y-intercept:

1Vmax=40 μM−1 min

Calculate Vmax:

Vmax=140=0.025 μM min−1


Calculation of Km

From the X-intercept:

−1Km=−1.5×102 mM−1

Solve for Km:

Km=11.5×102=6.67×10−3 mM=0.0067 mM

Equivalent to 0.67×10−2 mM.


Interpretation and Significance

  • Vmax=0.025 μM min−1 represents the maximum reaction velocity when enzyme is saturated.

  • Km=6.67×10−3 mM indicates that half-maximal velocity occurs at this substrate concentration, reflecting substrate affinity.


Summary Table

Parameter Calculated Value Unit
Vmax 0.025 μM min−1
Km 0.0067 (or 0.67×10−2) mM

Conclusion

By analyzing the intercepts of a Lineweaver-Burk plot, Vmax and Km can be precisely calculated. For the given data, the maximum velocity is 0.025 μM min−1, and the Michaelis constant is approximately 0.0067 mM. This process is fundamental in enzymology for characterizing enzyme behavior and substrate interactions accurately.

9 Comments
  • Aakansha sharma Sharma
    September 14, 2025

    For Vmax
    Given 1/v =40uM-min ,1/S = o means for Y intercept
    So we have to calculate Vmax = 1/40uM-min = 0.025 uM- min
    For Km
    Given 1/S=1.5×10(2)mM-, 1/V=0 means for X-intercept
    We have to calculate Km = 1/1.5×10(2)mM-=0.0067 so it can be written as 0.67× 10(-2) mM-
    The correct answer is (1) 0.025 µM min−1 and 0.67 ×10(-2)mM

  • Kanica Sunwalka
    September 14, 2025

    for Km
    1/s = 1.5×10^2
    On x axis – intercept i.e. 1/v =0
    so km = 1/ 1.5 x 10 ^2 = 0.0067 = 0.67x 10^-2 mM

    for Vmax
    1/v = 40
    On y axis – intercept 1/s =0
    so Vmax = 1/40 =0.025 uM min ^-1

    ans is 1 option

  • Kirti Agarwal
    September 14, 2025

    Op 1

  • Khushi Agarwal
    September 14, 2025

    The correct answer is (1) 0.025 µM min−1−1 and 0.67 \times 10^{-2}m
    Vmax = 1/40uM-1
    = 0.025 uM-1
    Km = 1/1.5×10(2)mM-=0.0067 = 0.67× 10(-2) mM-

  • Rishita
    September 14, 2025

    for Km
    1/s = 1.5×10^2
    On x axis – intercept i.e. 1/v =0
    so km = 1/ 1.5 x 10 ^2 = 0.0067 = 0.67x 10^-2 mM

    for Vmax
    1/v = 40
    On y axis – intercept 1/s =0
    so Vmax = 1/40 =0.025 uM min ^-1

  • Manisha choudhary
    September 14, 2025

    Option 1

  • Tanvi Panwar
    September 14, 2025

    for Vmax. ; 1/v=0+1/Vmax =.025uM min ^-1
    for Km; 0=Km/Vmax.(1/S)+1/Vmax. = 0.67x 10^-2 mM

  • Palak Sharma
    September 16, 2025

    km= 0.67 x 10-2 mM
    Vmax= 0.025 uM/min

  • Minal Sethi
    September 18, 2025

    1/v=0+1/Vmax =.025uM min -1
    for Km; 0=Km/Vmax.(1/S)+1/Vmax. = 0.67x 10^-2 mM

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