Presence if inhibitir in crude extract

Opt A, C, D

ACD is the right option

Cell free extract contained inhibitor bound enzyme
C. Purification steps gradually removed the inhibitors
D. The final fraction contained concentrated enzyme preparation

A. Cell free extract contained inhibitor bound enzyme
C. Purification steps gradually removed the inhibitors
D. The final fraction contained concentrated enzyme preparation
A,c,d right h
Kyunki starting me inhibitors enzyme k sath bind krnge but jese jese purification hota jayega bese bese inhibitors htate jaynge or purified enzyme ki specific activity increase hojayegi
Ye koi modification nhi h enzyme ka purification k time or purification gradual process ho rhi h

A, C, and D
Inhibitors are removed (C), previously bound inhibitory complexes present (A), enzyme is concentrated (D) → all leading to increased specific activity.

Inhibitors bound enz in extract
Removal of inhibitors during purification
Enz conc in fraction

Option 2 ACD correct answer…

Option 2means ACD is correct answer bcz modification in enzyme structure leads to decrease in enzyme activity…

specific activity of enzyme -increased when
* crude extract contains inhibitor bounded enzymes
* inhibitors less – enzyme activity increases
* concentrated enzyme – specific activity increases
so , option 2 is correct

Option 2

A,c&D

A,c,d are correct (option b)

A. Cell free extract contained inhibitor bound enzyme
C. Purification steps gradually removed the inhibitors
D. The final fraction contained concentrated enzyme preparation
All (A,c,d ) is correct

✔️

Enzyme’s activity loss due to structural modification.

correct answer is option (2) A, C and D.

Correct answer is option (2) A, C,D

A, C, D

A, C,and D

A, C,and D is the answer

Option A, C,and D is the answer

Specific activity of the enzyme increased in the purified fraction as compared to the cell free extract because cell free extract contained inhibitor bound enzyme and purification steps gradually removed the inhibitors.

Second option is incorrect which is the structure of enzyme get modified because if this was the case then there should be no activity rather then less activities because all the enzymes are in this same environment if structure modification happen it should be for all the enzyme and hence no activity

enzyme activity increased due to following reasons :
A. Cell free extract contained inhibitor bound enzyme
C. Purification steps gradually removed the inhibitors
D. The final fraction contained concentrated enzyme preparation

Acd

The increase in specific activity of the purified enzyme is best explained by the presence of inhibitors in the crude extract, removal of these inhibitors through purification steps, and concentration of enzyme. So A, C, D option is correct.

👉 Specific activity = enzyme activity ÷ total protein.
If specific activity increases, it usually means inhibitors and contaminating proteins were removed. So in A,C,D in this show increase of enzyme activity means increase of specific activity.

option a c d is right

A. Cell-free extract contained inhibitor-bound enzyme
C. Purification steps gradually removed the inhibitors
D. The final fraction contained concentrated enzyme preparation
A, C, and D are correct.
Because in the beginning, inhibitors are bound to the enzyme, but as purification proceeds, the inhibitors are gradually removed, and the specific activity of the purified enzyme increases.
This is not a modification of the enzyme — it is happening during purification, and purification is a gradual process.

The crude extract contains inhibitors so by their purification inhibitors are removed and their specific activity increases. Purification of enzymes removes non enzymatic proteins including inhibitors and the final step contained concentrated enzyme preparation. so option A C and D are correct.

option 2
A,C and D

A,C,D are the correct answer