105. A continuous reactor has a productivity of 0.5 𝑔/𝐼/ℎ. The volume of reactor required to produce 1.2 ton/day of the product is:
A. 100 𝐿
B. 1 𝑚3
C. 10 𝑚3
D. 100 𝑚3

Detailed Explanation:

In bioprocess engineering, it’s essential to determine the required reactor volume to meet a specified daily production target, especially in continuous operations. This calculation hinges on the productivity of the reactor, which is typically given in grams per liter per hour (g/L/h).

Given:

• Productivity = 0.5 g/L/h

• Production requirement = 1.2 tons/day = 1,200,000 grams/day

• We need to find the volume (V) in liters or cubic meters that will produce this amount.

Step-by-Step Calculation:

Step 1: Convert daily production into hourly production

Hourly production=1,200,000 g24 h=50,000 g/h\text{Hourly production} = \frac{1,200,000 \, \text{g}}{24 \, \text{h}} = 50,000 \, \text{g/h}Hourly production=24h1,200,000g​=50,000g/h

Step 2: Use the productivity to calculate required volume

Volume=Hourly productionProductivity=50,000 g/h0.5 g/L/h=100,000 L\text{Volume} = \frac{\text{Hourly production}}{\text{Productivity}} = \frac{50,000 \, \text{g/h}}{0.5 \, \text{g/L/h}} = 100,000 \, \text{L}Volume=ProductivityHourly production​=0.5g/L/h50,000g/h​=100,000L

Step 3: Convert liters to cubic meters

100,000 L=100 m3100,000 \, \text{L} = 100 \, \text{m}^3100,000L=100m3

Correct Answer:

D. 100 m³

Conclusion:

To produce 1.2 tons/day of product in a continuous reactor operating at 0.5 g/L/h, a reactor volume of 100 m³ is required. This calculation is a cornerstone of scale-up and process design in chemical and biochemical industries.